将参数传递给PowerShell中的scriptblock

时间:2013-05-02 20:33:28

标签: powershell scriptblock

我猜你不能这样做:

  $servicePath = $args[0]

  if(Test-Path -path $servicePath) <-- does not throw in here

  $block = {

        write-host $servicePath -foreground "magenta"

        if((Test-Path -path $servicePath)) { <-- throws here.

              dowork 
        }
  }

那么如何将我的变量传递给scriptblock $ block?

8 个答案:

答案 0 :(得分:41)

Keith's answer也适用于Invoke-Command,但您无法使用命名参数。应使用-ArgumentList参数设置参数,并且应以逗号分隔。

$sb = {param($p1,$p2) $OFS=','; "p1 is $p1, p2 is $p2, rest of args: $args"}
Invoke-Command $sb -ArgumentList 1,2,3,4

另见herehere

答案 1 :(得分:30)

scriptblock只是一个匿名函数。你可以在里面使用$args scriptblock以及声明一个param块,例如

$sb = {
  param($p1, $p2)
  $OFS = ','
  "p1 is $p1, p2 is $p2, rest of args: $args"
}
& $sb 1 2 3 4
& $sb -p2 2 -p1 1 3 4

答案 2 :(得分:5)

BTW,如果使用脚本块在单独的线程(多线程)中运行:

$ScriptBlock = {
    param($AAA,$BBB) 
    return "AAA is $($AAA) and BBB is $($BBB)"
}

$AAA = "AAA"
$BBB = "BBB1234"    
$null = Start-Job $ScriptBlock -ArgumentList $AAA,$BBB

然后产生:

$null = Start-Job $ScriptBlock -ArgumentList $AAA,$BBB    
Get-Job | Receive-Job
AAA is AAA and BBB is BBB1234

答案 3 :(得分:5)

对于任何想在2020年之前阅读并希望在远程会话脚本块中使用局部变量的人,可以从Powershell 3.0开始,通过“ $ Using”作用域修饰符直接在脚本块中使用局部变量。示例:

$MyLocalVariable = "C:\some_random_path\"
acl = Invoke-Command -ComputerName REMOTEPC -ScriptBlock {Get-Acl $Using:MyLocalVariable}

https://docs.microsoft.com/en-us/powershell/module/microsoft.powershell.core/invoke-command?view=powershell-7的示例9中找到

答案 4 :(得分:1)

我知道这篇文章有点陈旧,但我想把它作为一种可能的选择。只是稍微改变了之前的答案。

$foo = {
    param($arg)

    Write-Host "Hello $arg from Foo ScriptBlock" -ForegroundColor Yellow
}

$foo2 = {
    param($arg)

    Write-Host "Hello $arg from Foo2 ScriptBlock" -ForegroundColor Red
}


function Run-Foo([ScriptBlock] $cb, $fooArg){

    #fake getting the args to pass into callback... or it could be passed in...
    if(-not $fooArg) {
        $fooArg = "World" 
    }
    #invoke the callback function
    $cb.Invoke($fooArg);

    #rest of function code....
}

Clear-Host

Run-Foo -cb $foo 
Run-Foo -cb $foo 

Run-Foo -cb $foo2
Run-Foo -cb $foo2 -fooArg "Tim"

答案 5 :(得分:1)

默认情况下,PowerShell不会捕获ScriptBlock的变量。您可以通过调用GetNewClosure()来明确捕获,但是:

$servicePath = $args[0]

if(Test-Path -path $servicePath) <-- does not throw in here

$block = {

    write-host $servicePath -foreground "magenta"

    if((Test-Path -path $servicePath)) { <-- no longer throws here.

          dowork 
    }
}.GetNewClosure() <-- this makes it work

答案 6 :(得分:0)

三种示例语法:

$a ={ 
  param($p1, $p2)
  "p1 is $p1"
  "p2 is $p2"
  "rest of args: $args"
}
//Syntax 1:
Invoke-Command $a -ArgumentList 1,2,3,4 //PS> "p1 is 1, p2 is 2, rest of args: 3 4"
//Syntax 2:
&$a -p2 2 -p1 1 3      //PS> "p1 is 1, p2 is 2, rest of args: 3"
//Syntax 3:
&$a 2 1 3              //PS> "p1 is 2, p2 is 1, rest of args: 3"

答案 7 :(得分:0)

其他可能性: $a ={ 参数($p1,$p2) “p1 是 $p1” “p2 是 $p2” “其余的参数:$args” } $a.invoke(1,2,3,4,5)