我一整天都在这工作,但仍然在晚上8点没有运气。我想知道你们是否可以就修复它给我一些建议。我正在为大学建立一个Upload-gif共享系统。
无论如何,这是我的代码 -
<?php
ini_set('display_errors',1);
error_reporting(E_ALL);
mysql_connect("localhost","root","root") or die("Top Query");
mysql_select_db("UPLOAD") or die(mysql_error());
$count_query = mysql_query("SELECT NULL FROM details");
$count = mysql_num_rows($count_query);
//pagination
if(isset($_GET['page'])){
$page = preg_replace("#[^0-9]#","",$_GET['page']);
}else{
$page= 1;
}
$perPage = 5;
$lastPage = ceil($count / $perPage);
if($page < 1){
$page = 1;
}else if($page > $lastPage){
$page = $lastPage;
}
$limit = "LIMIT " .($page -1) * $perPage . ", $perPage";
//Query and gifs
$query = mysql_query("SELECT * FROM details ORDER BY date_added DESC") or die("2nd Query");
//Puts it into an array
$pagination="";
if($lastPage != 1){
if($page != $lastPage){
$next = $page + 1;
$pagination.='<a href="index.php?page='.$next.'">More</a>';
}
if($page != 1){
$prev = $page - 1;
$pagination.='<a href="index.php?page='.$prev.'">Back</a>';
}
}
?>
然后输出html -
<?php
while($info = mysql_fetch_array($query)){
$shortlink = "<a href=uploads/".$info['photo'].">".$info['photo']." </a>" ;
//Outputs the image and other data
echo "<article class='upload-post'>" . "<div class='crop'>";
echo "<a href=uploads/".$info['photo'].">";
echo "<img class='scale-with-grid' src=uploads/".$info['photo'] .">"."</a>";
echo "</div>";
echo "".$info['name'] . "<br/>";
echo "Reaction ".$info['reaction'] ."<br/>";
echo "In " .$info['category'] ." <br/>";
echo "On " .$info['date_added'] ." <br/>";
echo "Link: $shortlink";
echo "</article>";
}
?>
<?php echo $pagination;?>
我可以在页面之间切换但不限制页面上显示的帖子数量。我非常感谢帮助,因为截止日期并不太远。 提前一堆谢谢!
答案 0 :(得分:1)
您永远不会将$limit
附加到您的查询中。
答案 1 :(得分:0)
尝试以下作为替代......
...
//Query and gifs
$query = mysql_query("SELECT * FROM details ORDER BY date_added DESC ".$limit) or die("2nd Query");
//Puts it into an array
...