我的错误,我说清楚了:
我有一个简单的问题,但我是XSLT的新手:
我有2个xml文件:
usa1.xml
<?xml version="1.0" encoding="UTF-8"?>
<country>
<state name="CA">
<city name="Sunnyvale" county="Sant Clara">
<street number="123">
El Comino Ave.
</street>
</city>
<city name="San Jose" county="Sant Clara">
<street number="345">
De Anza Ave.
</street>
</city>
<city name="palo Alto" county="Sant Clara">
<street number="789">
Shoreline Ave.
</street>
</city>
</state>
</country>
usa2.xml
<?xml version="1.0" encoding="UTF-8"?>
<country>
<state name="CA">
<city name="Sunnyvale" county="Sant Clara">
<street number="999">
Homestead Ave.
</street>
</city>
<city name="San Jose" county="Sant Clara">
<street number="888">
Airport Ave.
</street>
</city>
</state>
</country>
我想使用XSLT将来自usa1.xml
的City Sunnyvale和San Jose的所有值和属性替换为来自usa2.xml
的数据。
想法输出为usa4.xml:
usa4.xml
<?xml version="1.0" encoding="UTF-8"?>
<country>
<state name="CA">
<city name="Sunnyvale" county="Sant Clara">
<street number="999">
Homestead Ave.
</street>
</city>
<city name="San Jose" county="Sant Clara">
<street number="888">
Airport Ave.
</street>
</city>
<city name="palo Alto" county="Sant Clara">
<street number="789">
Shoreline Ave.
</street>
</city>
</state>
</country>
我该怎么做?
我尝试了以下XSLT,但返回的输出不是我所期望的:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:param name="usaxml" select="'usa1.xml'" />
<xsl:variable name="address" select="document($usaxml)//" />
<xsl:template match="/">
<xsl:attribute name="number">
<xsl:value-of select="$address/@street" />
</xsl:attribute>
</xsl:template>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
答案 0 :(得分:1)
我会使用一个密钥来表示两个文件之间的交叉引用,但是如果你需要在文档之间使用密钥,那么代码对于XSLT 1.0来说有点复杂:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="k1" match="state/city" use="concat(../@name, '|', @name)"/>
<xsl:param name="usaxml" select="'test2013050302.xml'" />
<xsl:variable name="address" select="document($usaxml)" />
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="state/city">
<xsl:copy>
<xsl:variable name="this" select="."/>
<xsl:for-each select="$address">
<xsl:variable name="ref-data" select="key('k1', concat($this/../@name, '|', $this/@name))"/>
<xsl:choose>
<xsl:when test="$ref-data">
<xsl:apply-templates select="$ref-data/@* | $ref-data/node()"/>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="$this/@* | $this/node()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
所以主要输入是
<?xml version="1.0" encoding="UTF-8"?>
<country>
<state name="CA">
<city name="Sunnyvale" county="Sant Clara">
<street number="123">
El Comino Ave.
</street>
</city>
<city name="San Jose" county="Sant Clara">
<street number="345">
De Anza Ave.
</street>
</city>
<city name="palo Alto" county="Sant Clara">
<street number="789">
Shoreline Ave.
</street>
</city>
</state>
</country>
,参数文件test2013050302.xml
为
<?xml version="1.0" encoding="UTF-8"?>
<country>
<state name="CA">
<city name="Sunnyvale" county="Sant Clara">
<street number="999">
Homestead Ave.
</street>
</city>
<city name="San Jose" county="Sant Clara">
<street number="888">
Airport Ave.
</street>
</city>
</state>
</country>
转化结果是
<country>
<state name="CA">
<city name="Sunnyvale" county="Sant Clara">
<street number="999">
Homestead Ave.
</street>
</city>
<city name="San Jose" county="Sant Clara">
<street number="888">
Airport Ave.
</street>
</city>
<city name="palo Alto" county="Sant Clara">
<street number="789">
Shoreline Ave.
</street>
</city>
</state>
</country>
使用XSLT 2.0处理器和XSLT 2.0可以大大简化模板
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:key name="k1" match="state/city" use="concat(../@name, '|', @name)"/>
<xsl:param name="usaxml" select="'test2013050302.xml'" />
<xsl:variable name="address" select="document($usaxml)" />
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="state/city">
<xsl:copy>
<xsl:variable name="ref-data" select="key('k1', concat(../@name, '|', @name), $address)"/>
<xsl:choose>
<xsl:when test="$ref-data">
<xsl:apply-templates select="$ref-data/(@*, node())"/>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="@* , node()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>