userFunc中的doNotLinkIt

Question

我用以下的typoscript构建我的菜单

includeLibs.myadminmenu = typo3conf/ext/my_admin/user_makemenu.php
lib.userMenu = COA_INT
lib.userMenu.10 = HMENU
lib.userMenu.10 {
    special = directory
    special.value = 184
    modules = {$modules}
    entryLevel = 1
    1 = TMENU
    1.itemArrayProcFunc = user_myadminmenu->makemenu
    1 {
        NO = 1
        NO.allWrap = |
        ACT = 1
        ACT.allWrap = |
    }
}

这很好用，但在我的makemenu方法中我有以下

foreach($menuArr AS $i => $menu) {
    if (array_key_exists($menu['uid'], $this->paymentModules)) {
        if (! in_array($this->paymentModules[$menu['uid']], $modules)) {
            $menuArr[$i]['doNotLinkIt'] = 1;
        }
    }
}

这不起作用 - 我试过

unset($menuArr[$i])

这删除了菜单项，但我只是想让它不要链接，有没有办法做到这一点？

如果无法取消关联菜单项，是否可以将网址覆盖到其他网页？

Answer 1

另一种方法可能是：

（未测试的）

includeLibs.myadminmenu = typo3conf/ext/my_admin/user_makemenu.php
lib.userMenu = COA_INT
lib.userMenu.10 = HMENU
lib.userMenu.10 {
    special = directory
    special.value = 184
    modules = {$modules}
    entryLevel = 1
    1 = TMENU
    1 {
        NO = 1
        NO.allWrap = |
        NO.doNotLinkIt = 1
        NO.doNotLinkIt.if {
          # the userfunc needs to return a list of pids like
          # value = 10,12,24,44
          value.postUserFunc = user_myadminmenu->makemenu
          isInList.field = uid
        }
        ACT = 1
        ACT.allWrap = |
        ACT.doNotLinkIt < .NO.doNotLinkIt
    }
}

恕我直言，这更容易阅读和维护。