Question

我有一个包含folderName的NSString，我有一个看起来像这样的数组，

DATA (
    {
    FolderName = Posteingang;
    ID = 13000;
},
    {
    FolderName = Freigaben;
    ID = 13001;
},
    {
    FolderName = "My Drive";
    ID = 13002;
},
    {
    FolderName = gsb;
    ID = 13164;
},
    {
    FolderName = "my folder";
    ID = 13183;
}

我想将数组数据与NSString进行比较，以便我可以从字符串中删除不匹配的值。

for (NSString *FileName in ParsedData)
    {

        NSRange FileNameRange = [FileName rangeOfString:searchText options:NSCaseInsensitiveSearch];

        if (FileNameRange.location == NSNotFound) {

            [SearchData removeObject:[SearchData valueForKey:@"FolderName"]];

        }
    }

我有这个Fast Enumeration方法，我有Array SearchData。枚举方法查找数组中的数据，如果找不到该数据，则应将其从数组中删除.SearchData数组将显示在tableview中。

我一直在尝试上述方法，但它不起作用。

Answer 1

NSString *searchText = @"Posteingang";
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"FolderName = %@",searchText];
NSMutableArray *predarr = [NSMutableArray arrayWithArray:[yourDATAArray filteredArrayUsingPredicate:predicate]];
if([predarr count]!=0)
{
     NSLog(@"%@",predarr);
}

Answer 2

使用此：

NSString *matchString = @"Posteingang";
for (int i = 0; i > [dataArray count]; i++) // Here dataArray is your array
{
    NSMutableDictionary *allDict = [dataArray objectAtIndex:i];
    if ([[allDict objectForKey:@"FolderName"] isEqualToString:matchString]) {
        [dataArray removeObjectAtIndex:i];
    }

}

希望它可以帮到你。

Answer 3

NSString *stringToBeMatched = @"Freigaben";

for (NSDictionary *itemDic in array)
{
     if ([[itemDic objectForKey:@"FolderName"] isEqualToString:stringToBeMatched])
     {
         [dataArray removeObject:itemDic];
     }
}

Answer 4

尝试

NSArray *folders = @[@{@"FolderName":@"Posteingang",@"ID":@13000},
                     @{@"FolderName":@"Freigaben",@"ID":@13001},
                     @{@"FolderName":@"My Drive",@"ID":@13002},
                     @{@"FolderName":@"gsb",@"ID":@13164},
                     @{@"FolderName":@"my folder",@"ID":@13183}];

NSString *searchText = @"gsB";
//Choose a predicate that you want
//Case insensitive and diacritic search
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"FolderName LIKE [cd] %@",searchText];
//Case sensitive search
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"FolderName = %@",searchText];
//Any Matches
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"FolderName CONTAINS [cd] %@",searchText];

NSArray *filteredArray = [folders filteredArrayUsingPredicate:predicate];

编辑：使用快速枚举过滤

for (NSDictionary *dict in [SearchData copy]){

    NSString *folderName = dict[@"FolderName"];
    if([searchText localizedCaseInsensitiveCompare:folderName]){

         [SearchData removeObject:dict];

    }

 }

Answer 5

在上述所有答案的一点帮助之后，我自己想出了解决方案

    for (NSDictionary *dict in [SearchData copy]){

        NSString *folderName = [dict objectForKey:@"FolderName"];

        NSRange range= [folderName rangeOfString:searchText options:NSCaseInsensitiveSearch]; 
        if(range.location == NSNotFound){
             [SearchData removeObject:dict];

        }

    }

将数组的ValueForKey与NSString进行比较

5 个答案: