我有一个像这样的表结构:
TABLE NAME : counter
id | datetime | url | ip
-------------------------------------------
1 |2013-04-12 13:27:09 | url1 | ip01
2 |2013-04-13 10:55:43 | url2 | ip02
3 |2013-04-14 11:14:12 | url1 | ip03
4 |2013-04-15 23:23:55 | url2 | ip04
5 |2013-05-02 08:34:44 | url1 | ip03
使用智能SELECT
查询,我想获取3列:
Distinct URL | count of ip | count of distinct ip | for each distinct url | for each distinct url ------------------------------------------------------------------- url1 | 3 | 2 url2 | 2 | 2
我在by the help of this solution in stackoverflow下面提出了我的查询,它给出了我需要的前两列:
SELECT url, COUNT(*) AS total_ip FROM counter GROUP BY url ORDER BY total_ip DESC
但是如何将第3列添加到我的查询中呢?
你能帮帮我吗?
答案 0 :(得分:6)
正如您自己提到的,您可以使用DISTINCT
关键字来获取不同的URL
。使用COUNT
计算IP
和COUNT(DISTINCT ID)
,以便为每个IP
<{1}}获取不同的URL
试试这个:
SELECT DISTINCT URL AS D_URL
,COUNT(IP) AS IP
,COUNT(DISTINCT IP) AS D_IP
FROM counter
GROUP BY URL
输出:
╔═══════╦════╦══════╗
║ D_URL ║ IP ║ D_IP ║
╠═══════╬════╬══════╣
║ url1 ║ 3 ║ 2 ║
║ url2 ║ 2 ║ 2 ║
╚═══════╩════╩══════╝