Question

我有一个数据库表campaign_data。我需要选择customer_id广告系列中的关税存在差异。我怎么能用MySQL查询做到这一点。这是一些示例数据。

| CAMPAIGN_ID | CUSTOMER_ID |    CAMPAIGN_NAME | TARIFF |
---------------------------------------------------------
|           1 |           1 |         Richmond |    100 |
|           2 |           1 | Sutton Coldfield |     75 |
|           3 |           1 |           Putney |    100 |
|           4 |           1 |     Kentish Town |    100 |
|           5 |           1 |           Woking |    100 |
|           6 |           2 |         Chiswick |     90 |
|           7 |           2 |           Ealing |    100 |
|           8 |           2 |           Camden |    100 |
|           9 |           3 |          Croydon |     75 |
|          10 |           3 |         Croydon1 |    100 |
|          11 |           3 |          Archway |    100 |
|          12 |           4 |          Ealing0 |    100 |
|          13 |           4 |         Ealing01 |    100 |
|          14 |           4 |         Ealing02 |    100 |
|          15 |           4 |        Chingford |    100 |
|          16 |           4 |      chingford01 |    100 |

现在您可以看到客户ID 1和3具有不同的关税。我想选择它们并留下客户ID 4，因为它有相同关税的广告系列。

期望输出

| CUSTOMER_ID |
---------------
|           1 |
|           2 |
|           3 |

对于清除，您可以看到客户1有5条记录。如果在他的5个记录中，关税是相同的（100）我想避免，但如果关税不是一些，因为4个记录有100个，一个有75个，我想选择。

Answer 1

SELECT customer_id, count(DISTINCT tariff) as tariffs 
FROM campaign_data 
GROUP BY customer_id 
HAVING tariffs > 1

Answer 2

select
  customer_id,
  tariff
from campaign_data
group by customer_id
having sum(tariff)/count(tariff) <> tariff;

Answer 3

你正在寻找这个

SELECT customer_id
FROM campaign_data 
GROUP BY customer_id 
HAVING count(DISTINCT tariff) > 1

http://sqlfiddle.com/#!2/48b6e/31

SELECT记录WHERE行在特定列上有差异

3 个答案: