我有以下代码,我想在其中创建一个具有动态背景的div
:
public interface Template extends SafeHtmlTemplates {
@Template("<div class='imageDiv' style=\"background-image: url({0});\"/>")
SafeHtml content(String picture);
}
public void render(SafeHtmlBuilder safeHtmlBuilder, final T model) {
SafeHtml html = TEMPLATE.content(picture);
safeHtmlBuilder.append(html);
}
运行应用程序后,首先我收到了此警告:
Template with variable in CSS attribute context:
The template code generator cannot guarantee HTML-safety of the template
然后出错:
java.lang.NullPointerException: null
at com.google.gwt.safehtml.shared.SafeHtmlUtils.htmlEscape(SafeHtmlUtils.java:156)
at xx.xx.xx.xx.xx.ImageItemCell_TemplateImpl.content(ImageItemCell_TemplateImpl.java:14)
at xx.xx.xx.xx.xx.ImageItemCell.render(ImageItemCell.java:53)
当我尝试将图片设置为SafeUri时:
SafeUri uri = UriUtils.fromTrustedString(picture);
SafeHtml html = TEMPLATE.content(uri);
我得到了这个不同的错误:
[ERROR] - SafeUri can only be used as the entire value of a URL attribute.
Did you mean to use java.lang.String or SafeHtml instead?
在这种情况下我该怎么做?
感谢。
答案 0 :(得分:1)
您必须使用SafeStyles
:
public interface Template extends SafeHtmlTemplates {
@Template("<div class='imageDiv' style='{0}'></div>")
SafeHtml content(SafeStyles picture);
}
public void render(SafeHtmlBuilder safeHtmlBuilder, final T model) {
SafeHtml html = TEMPLATE.content(SafeStyleUtils.forBackgroundImage(picture));
safeHtmlBuilder.append(html);
}
(假设picture
此处为SafeUri
)