我正在尝试对机器人进行编码,而且我的情况令人困惑。我需要将一个指向对象的数组传递给一个类的构造函数。但是,在将数组传递给构造函数之前,我无法填充数组。为了解决这个问题,我想传递一个指向所述数组的指针,并从指针访问它的元素。问题是我是C ++的新手,所以我不确定语法。你能帮助我吗?
主文件的代码
class RobotDemo : public SimpleRobot
{
Joystick stick;
JoystickOne joyOne;
Victor *victors [8];
public:
RobotDemo(void):
stick(1),
joyOne(&stick)// these must be initialized in the same order
// as they are declared above.
/*It doesnt seem like I can do anything but initialize things here*/
{
/*Populate array with pointers to victors. Will need to update channels*/
for (int x = 1; x <= 7; x++) {
victors[x] = new Victor(x);
}
/*And I don't think I can initialize anything here*/
myRobot.SetExpiration(0.1);
}
/**
* Drive left & right motors for 2 seconds then stop
*/
void Autonomous(void)
{
}
/**
* Runs the motors with arcade steering.
*/
void OperatorControl(void)
{
myRobot.SetSafetyEnabled(true);
while (IsOperatorControl())
{
joyOne.testForActions(); /*Check joystick one for actions*/
Wait(0.005); // wait for a motor update time
}
}
/**
* Runs during test mode
*/
void Test() {
}
};
START_ROBOT_CLASS(RobotDemo);
以下是JoystickOne类扩展的JoystickInput类的代码
//the .h
#ifndef JOYSTICKINPUT_H
#define JOYSTICKINPUT_H
#include "WPILib.h"
class JoystickInput {
public:
JoystickInput(Joystick*);
JoystickInput(Joystick*, Victor* [8]);
Joystick * joystick;
bool buttons [10];
Victor** victors [8];
bool buttonClicked(int id);
virtual void testForActions();
};
#endif
//and the .cpp
#include "JoystickInput.h"
JoystickInput::JoystickInput(Joystick * joy) {
joystick = joy;
for (int x = 0; x < 10; x++) {
buttons[x] = false;
}
}
JoystickInput::JoystickInput(Joystick * joy, Victor* vicArray [8]) {
joystick = joy;
for (int x = 0; x < 10; x++) {
buttons[x] = false;
}
for (int n = 0; n <=7; n++) {
*victors[n] = vicArray[n];
}
}
bool JoystickInput::buttonClicked(int id) {
if (buttons[id] == false and joystick->GetRawButton(id) == true) {
buttons[id] = true;
return true;
} else if (buttons[id] == true and joystick->GetRawButton(id) == false) {
buttons[id] = false;
return false;
} else {
return false;
}
}
void JoystickInput::testForActions() {
}
我要求你们帮助我做的是重新设计JoystickInput()的构造函数,以便它还获取一个指针数组(指向Victors),并对数组元素执行方法。谷歌搜索它没有任何有用的东西。我自己研究的更多,但已经过了几天,我仍然坚持这个。
感谢您的帮助(如果没有,那么至少阅读我的帖子)!
答案 0 :(得分:2)
你应该可以使用:
JoystickInput(Joystick*, Victor**, int);
然后将vicArray传递给构造函数。如果victors可以是长度为8的数组之外的其他任何东西,那么你也应该将长度作为参数传递,因为c ++无法从指针中找到数组的长度。
答案 1 :(得分:1)
每当类型变得复杂(函数或数组)时,请使用typedef:
typedef char char_buffer_type[8]; //char_buffer_type is an array
typedef char (*char_buffer_ptr)[8]; //char_buffer_ptr is a pointer to an array
typedef char (&char_buffer_ref)[8]; //char_buffer_ref is a reference to an array
typedef int main_type(int, char**); //main_type is a "int(int, char**)" function
typedef Victor*(array_of_ptr)[8]; //array_of_ptr is an array of 8 Victor*
此外,您应该将值命名为8
和10
。
class JoystickInput {
public:
static const int victor_count = 8;
static const int button_count = 10;
typedef Victor*(array_of_victor_ptr)[victor_count];
JoystickInput(Joystick*){}
JoystickInput(Joystick*, array_of_victor_ptr& vicArray);
bool buttonClicked(int id){return true;}
virtual void testForActions(){}
Joystick * joystick;
bool buttons [button_count];
array_of_victor_ptr victors; //that's simpler
};
//then pass this one by reference
JoystickInput::JoystickInput(Joystick * joy, array_of_victor_ptr& vicArray) {
joystick = joy;
for (int x = 0; x < button_count; x++) {
buttons[x] = false;
}
for (int n = 0; n < victor_count; n++) {
victors[n] = vicArray[n]; //don't have to dereference here anymore
}
}
Proof of compilation。 Typedef很精彩。使用它们。