Question

我希望在电子邮件中包含员工姓名时显示与其关联的名称和电子邮件。用户可以拥有多个电子邮件。

employee
id   name 
1    Steve Been
2    Rob Kem
3    Bob Kimi

Emails
emplyee_id email
1          steve@domain.com
1          007@domain.com
1          Been@domain.com
2          Robkem@domain.com 
2          Rob.Kem@domain.com 
3          Boooob@domain.com
3          kimi@domain.com

查询不应区分大小写。我希望此查询向我显示如下内容：

name            email
Steve Been      steve@domain.com
Steve Been      Been@domain.com
Rob Kem         Robkem@domain.com 
Rob Kem         Rob.Kem@domain.com       
Bob Kimi        kimi@domain.com

我尝试了这个但是输出空了：

select empl.Name as 'employee Name', em.email as 'Product Name'

from email em JOIN employee empl
ON em.employee_id = empl.ID

WHERE FIND_IN_SET(LOWER(empl.Name),LOWER(em.Name))

Answer 1

尝试

SELECT e.name,
       m.email
  FROM emails m JOIN
       employee e ON m.emplyee_id = e.id
 WHERE INSTR(m.email, SUBSTRING_INDEX(e.name, ' ', 1)) > 0 
    OR INSTR(m.email, SUBSTRING_INDEX(e.name, ' ', -1)) > 0

<强> SQLFiddle

除非其中一个字符串是二进制字符串，否则

INSTR()不区分大小写，但您可以随时添加LOWER()以获得良好的衡量标准。

更新：根据您的其他请求，您可以使用此类

这样的查询来执行此操作

SELECT name, 
       total, 
       matched, 
       total - matched unmatched
  FROM (
SELECT e.name,
       COUNT(*) total,
       SUM(CASE WHEN INSTR(m.email, SUBSTRING_INDEX(e.name, ' ', 1)) > 0 
                  OR INSTR(m.email, SUBSTRING_INDEX(e.name, ' ', -1)) THEN 1 ELSE 0 END) matched
  FROM emails m JOIN
       employee e ON m.emplyee_id = e.id
 GROUP BY e.id, e.name) q

<强> SQLFiddle

检查员工电子邮件是否包含其姓名 - 不区分大小写

1 个答案: