我正在使用此链接转换的代码示例http://bl.ocks.org/mbostock/3903818 我已经设置了自己的代码来解析csv文件而不是tsv。但是,当我从New视图切换到Existing视图时,我得到错误解析D3 d =“”在Javascript控制台中重复两次。不确定是否是导致错误的每个函数的数据。代码如下:
var margin = {top: 20, right: 50, bottom: 30, left: 60},
width = 878 - margin.left - margin.right,
height = 500 - margin.top - margin.bottom;
var parseDate = d3.time.format("%Y%d%m").parse;
var x = d3.time.scale()
.range([0, width]);
var y = d3.scale.linear()
.range([height, 0]);
var color = d3.scale.category10();
var xAxis = d3.svg.axis()
.scale(x)
.orient("bottom");
var yAxis = d3.svg.axis()
.scale(y)
.orient("left");
var line = d3.svg.line()
.interpolate("basis")
.x(function(d) { return x(d.date); })
.y(function(d) { return y(d.price); });
var tooltip = d3.select("body")
.append("div")
.style("position", "absolute")
.style("z-index", "10")
.style("visibility", "hidden")
.text("a simple tooltip");
var svg = d3.select("#chart").append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")")
//Add grid lines
function make_X_axis() {
return d3.svg.axis()
.scale(x)
.orient("bottom")
.ticks(6)
}
function make_Y_axis() {
return d3.svg.axis()
.scale(y)
.orient("left")
.ticks(9)
}
//Parse data
d3.csv("data/newdata2.csv", function(error, data) {
color.domain(d3.keys(data[0]).filter(function(key) { return key !== "date"; }));
data.forEach(function(d) {
d.date = parseDate(d.date);
d["New"] = +d["New"];
d["Existing"] = +d["Existing"];
});
var homes = color.domain().map(function(name) {
return {
name: name,
values: data.map(function(d) {
return {date: d.date, price: +d[name]};
})
};
});
x.domain(d3.extent(data, function(d) { return d.date; }));
y.domain([
d3.min(homes, function(c) { return d3.min(c.values, function(v) { return v.price; }); }),
d3.max(homes, function(c) { return d3.max(c.values, function(v) { return v.price; }); })
]);
svg.append("g")
.attr("class", "grid")
.attr("transform", "translate(0," + height + ")")
.call(make_X_axis()
.tickSize(-height, 0, 0)
.tickFormat("")
)
svg.append("g")
.attr("class", "grid")
.call(make_Y_axis()
.tickSize(-width, 0, 0)
.tickFormat("")
)
svg.append("g")
.attr("class", "x axis")
.attr("transform", "translate(0," + height + ")")
.call(xAxis);
svg.append("g")
.attr("class", "y axis")
.call(yAxis)
svg.append("text")
.attr("transform", "rotate(-90)")
.attr("y", 6)
.attr("dy", ".71em")
.style("text-anchor", "end")
.text("Thousands($)");
var city = svg.selectAll(".city")
.data(homes)
.enter().append("g")
.attr("class", "city");
city.append("path")
.attr("class", "line")
.attr("d", function(d) { return line(d.values); })
.style("stroke", function(d) { return color(d.name); });
city.append("text")
.datum(function(d) { return {name: d.name, value: d.values[d.values.length - 1]}; })
.attr("transform", function(d) { return "translate(" + x(d.value.date) + "," + y(d.value.price) + ")"; })
.attr("x", 3)
.attr("dy", ".35em")
.text(function(d) { return d.name; });
d3.selectAll("input").on("change", change);
var timeout = setTimeout(function() {
d3.select("input[value=\"Existing\"]").property("checked", true).each(change);
}, 2000);
function change() {
clearTimeout(timeout);
city = this.value;
// First transition the line & label to the new city.
var t0 = svg.transition().duration(750);
t0.selectAll(".line").attr("d", line);
t0.selectAll(".label").attr("transform", transform).text(city);
// Then transition the y-axis.
y.domain(d3.extent(data, function(d) { return d[city]; }));
var t1 = t0.transition();
t1.selectAll(".line").attr("d", line);
t1.selectAll(".label").attr("transform", transform);
t1.selectAll(".y.axis").call(yAxis);
}
function transform(d) {
return "translate(" + x(d.date) + "," + y(d[city]) + ")";
}
});
答案 0 :(得分:1)
在您创建该行的代码中,您引用d.values
作为绘制路径的数据:
city.append("path")
.attr("class", "line")
.attr("d", function(d) { return line(d.values); })
.style("stroke", function(d) { return color(d.name); });
但是,在更改处理程序中,您只需调用(两次)
t0.selectAll(".line").attr("d", line);
使两位代码保持一致应解决问题,即将更改函数中的两个调用更改为
t0.selectAll(".line").attr("d", function(d) { return line(d.values); });