Question

我需要调用一个接受stream参数的方法。该方法将文本加载到流中，该流通常是文件。我想简单地用流的内容填充一个字符串，而不是将其写入文件。我该怎么做？

Answer 1

将MemoryStream与StreamReader一起使用。类似的东西：

using (MemoryStream ms = new MemoryStream())
using (StreamReader sr = new StreamReader(ms))
{
   // pass the memory stream to method
   ms.Seek(0, SeekOrigin.Begin); // added from itsmatt
   string s = sr.ReadToEnd();
}

Answer 2

使用StringWriter充当字符串的流：

StringBuilder sb = new StringBuilder();
StringWriter sw = new StringWriter(sb);
CallYourMethodWhichWritesToYourStream(sw);
return sb.ToString();

Answer 3

查找MemoryStream类

Answer 4

MemoryStream ms = new MemoryStream();
YourFunc(ms);
ms.Seek(0, SeekOrigin.Begin);
StreamReader sr = new StreamReader(ms);
string mystring = sr.ReadToEnd();

是一种方法。

Answer 5

你可以这样做：

string s = "Wahoo!";
int n = 452;

using( Stream stream = new MemoryStream() ) {
  // Write to the stream

  byte[] bytes1 = UnicodeEncoding.Unicode.GetBytes(s);
  byte[] bytes2 = BitConverter.GetBytes(n);
  stream.Write(bytes1, 0, bytes1.Length);
  stream.Write(bytes2, 0, bytes2.Length);

如何在.Net中使用String作为流？

5 个答案: