正则表达式模式需要PHP - 字符串和单词的混合

Question

我需要特定正则表达式匹配的帮助。这是PHP。 （编辑wordpress插件）

我们说字符串是

"[youtube|sjdhskajxn|This is a string|This is also a string|44|55]"

我想提取

{0} -> youtube
{1} -> sjdhskajxn
{2} -> This is a string
{3} -> This is also a string
{4} -> 44
{5} -> 55

此外，要匹配的项目数也不会保持不变。

Answer 1

$string = '[youtube|sjdhskajxn|This is a string|This is also a string|44|55]';
$string = str_replace(array('[',']'), '', $string); //remove brackets

$result = explode('|', $string); //explode string into an array

Answer 2

使用explode()功能

$str = "[youtube|sjdhskajxn|This is a string|This is also a string|44|55]";
$str = str_replace(array('[',']'), '', $str);
$pieces = explode("|", $str);

Answer 3

如果要允许Unicode字符：

preg_match_all('/[\pL\pN\pZ]+/u', $subject, $result, PREG_PATTERN_ORDER);
$result = $result[0];

否则（只是ASCII），它更简单：

preg_match_all('/[a-z0-9\s]+/i', $subject, $result, PREG_PATTERN_ORDER);
$result = $result[0];

Answer 4

$raw = '[youtube|sjdhskajxn|This is a string|This is also a string|44|55]';

// remove brackets only at beginning/end
$st = preg_replace('/(^\[)|(\]$)/', '', $raw);

$parts = explode('|', $st);