inode
/proc/**/fd/*
/proc/**/exe
找到可执行路径的Linux内核模块我怎样才能实现这一点,以便从inode编号使用fd得到可执行文件的路径?
答案 0 :(得分:0)
proc_inode
struct和PROC_I
macro都是内部的。请参阅[PATCH 27/28] proc: Make the PROC_I() and PDE() macros internal toprocfs [RFC]。
相反,如何迭代inode的dentry列表呢?您可以使用dentry_path_raw()查找/*/fd/*
路径名称:
//struct inode *proc_inode;
struct dentry *dentry;
pid_t pid;
int found_match = 0;
printk(KERN_DEBUG "superblock type name: %s\n", proc_inode->i_sb->s_type->name);
// An inode's dentry list is protected by the i_lock. See:
// - "dcache->d_inode->i_lock protects: i_dentry, d_u.d_alias, d_inode of aliases"
// http://lxr.free-electrons.com/source/fs/dcache.c?v=4.0#L48
// - The implementation of d_prune_aliases()
// http://lxr.free-electrons.com/source/fs/dcache.c?v=4.0#L882
spin_lock(&proc_inode->i_lock);
hlist_for_each_entry(dentry, &proc_inode->i_dentry, d_u.d_alias) {
char buf[64];
const char *path_raw;
char c;
path_raw = dentry_path_raw(dentry, buf, sizeof(buf));
// dentry_path_raw() places the path into `buf'. If `buf' is not large
// enough, then continue on to the next dentry.
if (!(buf <= path_raw && path_raw <= buf + sizeof(buf) - 1)) {
printk(KERN_DEBUG "`buf' not large enough, dentry_path_raw() returned %ld\n", PTR_ERR(path_raw));
continue;
}
printk(KERN_DEBUG "path_raw = %s\n", path_raw);
// We're looking to match: ^/(\d*)/fd/
if (*path_raw++ != '/') continue;
pid = 0;
for (c = *path_raw; c; c = *++path_raw) {
if ('0' <= c && c <= '9') {
pid = 10 * pid + (c - '0');
} else {
break;
}
}
if (*path_raw++ != '/') continue;
if (*path_raw++ != 'f') continue;
if (*path_raw++ != 'd') continue;
if (*path_raw != '/' && *path_raw != '\0') continue;
// Found a match. Break the dentry list loop.
found_match = 1;
printk(KERN_DEBUG "breaking dentry list loop\n");
break;
}
spin_unlock(&proc_inode->i_lock);
if (found_match) {
printk(KERN_DEBUG "pid = %d\n", (int)pid);
}
编辑:我已将示范项目上传到GitHub:
https://github.com/dtrebbien/so16317923-proc-fs-kernel-module