我需要帮助mysql查询根据一系列进入和退出日期更新同一个表的新列。
下面是表格:
╔════╦═══════════╦═════════════╦═════════════╦════════════════════╗
║ ID ║ PLACE ║ ENTRYDATE ║ EXITDATE ║ LAST_PLACE_VISITED ║
╠════╬═══════════╬═════════════╬═════════════╬════════════════════╣
║ 1 ║ Delhi ║ 1-Jan-2012 ║ 5-Jan-2012 ║ ║
║ 1 ║ Agra ║ 10-Jan-2012 ║ 11-Jan-2012 ║ ║
║ 1 ║ Bangalore ║ 21-Jan-2012 ║ 24-Jan-2012 ║ ║
║ 1 ║ Mumbai ║ 12-Jan-2012 ║ 19-Jan-2012 ║ ║
║ 2 ║ LA ║ 1-Mar-2012 ║ 3-Mar-2012 ║ ║
║ 2 ║ SFO ║ 10-Mar-2012 ║ 14-Mar-2012 ║ ║
║ 2 ║ NY ║ 4-Mar-2012 ║ 9-Mar-2012 ║ ║
║ 3 ║ Delhi ║ 12-Apr-2012 ║ 13-Apr-2012 ║ ║
╚════╩═══════════╩═════════════╩═════════════╩════════════════════╝
ENTRYDATE和EXITDATE 的数据类型为DATE
。
从上表我需要编写一个查询,根据ID的输入和退出日期更新“Last_Place_Visited”列。
对此查询的任何帮助都会非常适合。
感谢。 Bhargav
答案 0 :(得分:2)
由于MySQL
不支持窗口函数,这是一个非常混乱的问题,
UPDATE TravelTbl a
INNER JOIN
(
SELECT a.ID,
a.Place,
a.EntryDate,
a.ExitDate,
b.Place Last_Place_Visited
FROM
(
SELECT ID,
Place,
EntryDate,
ExitDate,
Last_Place_Visited,
@grp := if(@ID = ID, @grp ,0) + 1 GRP_RecNo,
@ID := ID
FROM TravelTbl,
(SELECT @ID := '', @grp := 0) vars
ORDER BY EntryDate
) a
LEFT JOIN
(
SELECT ID,
Place,
EntryDate,
ExitDate,
Last_Place_Visited,
@grp2 := if(@ID2 = ID, @grp2 ,0) + 1 GRP_RecNo,
@ID2 := ID
FROM TravelTbl,
(SELECT @ID2 := '', @grp2 := 0) vars
ORDER BY EntryDate
) b ON a.ID = b.ID AND
a.GRP_RecNo = b.GRP_RecNo + 1
) b ON a.ID = b.ID AND
a.Place = b.Place AND
a.EntryDate = b.EntryDate AND
a.ExitDate = b.ExitDate AND
b.Last_Place_Visited IS NOT NULL
SET a.Last_Place_Visited = b.Last_Place_Visited
输出
╔════╦═══════════╦═════════════╦═════════════╦════════════════════╗
║ ID ║ PLACE ║ ENTRYDATE ║ EXITDATE ║ LAST_PLACE_VISITED ║
╠════╬═══════════╬═════════════╬═════════════╬════════════════════╣
║ 1 ║ Delhi ║ 1-Jan-2012 ║ 5-Jan-2012 ║ (null) ║
║ 1 ║ Agra ║ 10-Jan-2012 ║ 11-Jan-2012 ║ Delhi ║
║ 1 ║ Bangalore ║ 21-Jan-2012 ║ 24-Jan-2012 ║ Mumbai ║
║ 1 ║ Mumbai ║ 12-Jan-2012 ║ 19-Jan-2012 ║ Agra ║
║ 2 ║ LA ║ 1-Mar-2012 ║ 3-Mar-2012 ║ (null) ║
║ 2 ║ SFO ║ 10-Mar-2012 ║ 14-Mar-2012 ║ NY ║
║ 2 ║ NY ║ 4-Mar-2012 ║ 9-Mar-2012 ║ LA ║
║ 3 ║ Delhi ║ 12-Apr-2012 ║ 13-Apr-2012 ║ (null) ║
╚════╩═══════════╩═════════════╩═════════════╩════════════════════╝
答案 1 :(得分:0)
我试图修改表格本身:
UPDATE T SET LAST_PLACE_VISITED = (
SELECT t2.PLACE
FROM T t2
WHERE t2.EXITDATE = (
SELECT MAX(t1.EXITDATE)
FROM T t1
WHERE t1.ID = ID
AND t1.EXITDATE < EXITDATE
));
MySQL不允许这样做:
You can't specify target table 'T' for update in FROM clause:
但是您可以使用视图或临时表并使用它:
更新:已插入LIMIT 1
,用于处理不同ID的EXITDATE最大值出现多次的情况。缺点:我们无法预测哪一行具有最大值。
更新2:已添加条件AND t2.ID = t0.ID
SELECT t0.ID, t0.PLACE, t0.ENTRYDATE, t0.EXITDATE, (
SELECT t2.PLACE
FROM T t2
WHERE t2.EXITDATE = (
SELECT MAX(t1.EXITDATE)
FROM T t1
WHERE t1.ID = t0.ID
AND t1.EXITDATE < t0.EXITDATE
)
AND t2.ID = t0.ID
LIMIT 1
) AS LAST_PLACE_VISITED
FROM T t0;
查看我的SQLFiddle demo