Question

我想知道是否可以从传递给Each的块中放置的for循环中返回Ruby中的每个迭代器。

def find member = ""

        productHash = {}

            #@entries is a hash, with both the keys and values being strings
            #the member parameter is a string

        @entries.each do |key, value|

            for i in 0...member.size

                if(key[i] != member[i])
                    next #the next keyword doesn't work...all it does is return to the for iterator.  I'm looking for a keyword that would return to the each iterator, and allow each to pass back in the next key-value pair.
                end

            end

            productHash[key] = value


        end

        productHash

end

我想要完成的是：当我看到成员参数中的字符与给定键中的相应字符不匹配时，我转到下一个键值对。

Answer 1

看起来您正在尝试进行某种比较，如果密钥与member指定的特定前缀匹配，那么您将进行分配。

此代码应在功能上类似：

def find(member = "")
  hash = { }

  @entries.each do |key, value|
    # Unless key begins with prefix, skip it.
    next unless (key[0, prefix.length] == prefix)

    hash[key] = value
  end

  hash
end

Ruby中没有正式的goto声明，许多人认为这是件好事，但这意味着破坏嵌套块可能有点棘手。

但是，如果你以正确的方式解决问题，那么几乎总会有一个足够优雅的解决方案。

<强>更新

要打破嵌套循环，方法可能是：

list.each do |i|
  broken = false

  inner_list.each do |j|
    if (j > 10)
      broken = true
      break
    end
  end

  break if (broken)
end

从For Loop返回每个迭代器

1 个答案: