Question

我来自nhibernate背景，我想知道如何在serer端自动生成Guid而不是在数据库端进行往返？

在流利的nhibernate中，它很简单

   Id(x => x.Id).GeneratedBy.GuidComb();

Answer 1

如果要在服务器上生成密钥，只需在代码中执行此操作：

public class TestObject 
{
    public TestObject() 
    {
        Id = Guid.NewGuid();
    }
    public Guid Id { get; set; }
}

如果您希望数据库生成密钥，请使用DatabaseGenerated属性：

public class TestObject 
{
    [DatabaseGenerated(DatabaseGeneratedOption.Identity)]
    public Guid Id { get; set; }
}

如果您正在使用顺序GUID，那么目前没有简单的答案。一些可以帮助您走上正确道路的例子：

Generating IDs in the SaveChanges method
Calling your own NewGuid method
Use a non-EF method to change the default value for the identity field从NEWID()到NEWSEQUENTIALID()

Answer 2

此代码可满足您的需求：

using System;
using System.Runtime.InteropServices;
public static class SequentialGuidProvider
{
    [DllImport("rpcrt4.dll", SetLastError = true)]
    private static extern int UuidCreateSequential(out Guid guid);

    private static Guid CreateGuid()
    {
        Guid guid;
        int result = UuidCreateSequential(out guid);
        if (result == 0)
            return guid;
        else
            return Guid.NewGuid();
    }

    public static Guid GuidComb(this Nullable<Guid> guid)
    {
        if (!guid.HasValue) guid = SequentialGuidProvider.CreateGuid();
        return guid.Value;
    }
}

测试类：

public class TestObject
{
    public TestObject()
    {
    }

    private Nullable<Guid> _guid = null;
    public Guid Id
    {
        get
        {
            _guid = _guid.GuidComb();
            return _guid.Value();
        }
        set
        {
            _guid = value;
        }
    }
}

测试代码：

    static void Main(string[] args)
    {
        TestObject testObject1 = new TestObject();
        TestObject testObject2 = new TestObject();
        TestObject testObject3 = new TestObject();
        //simulate EF setting the Id
        testObject3.Id = new Guid("ef2bb608-b3c4-11e2-8d9e-00262df6f594");

        //same object same id
        bool test1 = testObject1.Id == testObject1.Id;
        //different object different id
        bool test2 = testObject1.Id != testObject2.Id;
        //EF loaded object has the expected id
        bool test3 = testObject3.Id.Equals(new Guid("ef2bb608-b3c4-11e2-8d9e-00262df6f594"));
    }

Answer 3

从EF 6.1.3开始，当使用GUID作为PK时，数据库默认值[newsequentialid()或newid()]可能很重要见entity framework use a guid as the primary key。

在服务器端实体框架5上生成Guid？

3 个答案: