我有以下问题。当我尝试通过HTML表单更新用户名值时。 这是我的HTML表单:
<form action="namechanging.php" method="post">
<br>
<fieldset>
<span class="ico user-ico"></span>
<input name="ingamename" type="text" class="field" value="Example: John_Doe" title="Example: John_Doe" />
</fieldset>
<center><input name="submit" type="submit" class="submit btn blue-btn" value="Change Name" /></center>
</form>
这是我的namechanging.php文件:
<?php
session_start();
$_SESSION['ingamename'] = $_POST['ingamename'];
$newingamename = $_SESSION['ingamename'];
$nc = $_SESSION['nc'];
if($nc < 1){
$updateresult = '<strong>Error:</strong> You do not have any name changes left. Donate for more...';
header("Location: ucp-home-error.php");
}
else {
$con=mysqli_connect("localhost","USERNAME","PASS","DB-NAME");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$newnc = $nc - 1;
mysqli_query($con,"UPDATE users SET Username=$newingamename WHERE Username='$_SESSION[user]' ");
mysqli_query($con,"UPDATE users SET NameChanges=$newnc
WHERE Username='$_SESSION[user]'");
$updateresult = 'Your In-Game Name was changed successfully. Please re-log!';
header("Location: ucp-home-success.php");
}
mysqli_close($con);
$_SESSION['updateresult'] = $updateresult;?>
它可以从$ nc中删除-1,但它不会更改用户名。您还应该知道用户名已保存在会话中,这是我登录到身份验证页面的用户名。 这是我的auth.php文件:
<?php
include("sql.php");
session_start();
function Destroy() {
unset($_SESSION['UID']);
unset($_SESSION['USERNAME']);
unset($_SESSION['FULL NAME']);
header("location: account-log-in-restricted.php");
}
if(isset($_SESSION['UID']) && isset($_SESSION['USERNAME'])) {
$UID = $_SESSION['UID'];
$username = $_SESSION['USERNAME'];
$qry = mysql_query("SELECT * FROM `users` WHERE `UID` = '$UID' AND `Username` = '$username'");
if(mysql_num_rows($qry) != 1) { Destroy(); }
} else { Destroy(); }
?>
答案 0 :(得分:1)
这可能令人窒息:
mysqli_query($con,"UPDATE users WHERE Username='$_SESSION[user]' SET Username=$newingamename");
1 ^^^^^^^^^^^^^ 2 ^^^^^^^^^^^^
在(1)中,当你想要的是$_SESSION[user]
时($_SESSION['user']
附近有引号),这相当于说user
。
在(2)中,你需要在$ newingamename周围加上单引号。
注意:其余内容是根据以下原始答案进行编辑的:(a)合并PHP和MySQL修复程序,以及(b)使用mysqli
参数绑定重新构建代码安全。
此外,MySQL查询错误:SET
出现在WHERE
之前。
将所有这些放在一起,使用mysqli
绑定参数进行代码(和职业)安全性,你得到这个:
$stmt = mysqli_prepare($con, 'UPDATE users SET username=? WHERE username = ?');
mysqli_stmt_bind_param($stmt, 'ss', $newingamename, $_SESSION['user']);
mysqli_stmt_execute($stmt);
对其他UPDATE
进行类似的更改。