我有一个需要转换为分层的平面xml文件。我使用了xsl:for-each-group help needed的嵌套分组思想。它除了几个问题外大部分都在工作：
1）元素root1和root2没有显示。
2）元素level21的位置不正确。 sequencecount = 2的第一个level21应该在2个level2元素之间。
非常感谢任何帮助。
感谢。
源XML
<root>
<root1>1234</root1>
<root2>5678</root2>
<level1>
<a>line 1</a>
<b>line 2</b>
<c>line 3</c>
</level1>
<level2>
<d>line 4</d>
<e>line 5</e>
<f>line 6</f>
<g>line 7</g>
</level2>
<level3>
<h>line 8</h>
<i>line 9</i>
<j>line 10</j>
<k>line 11</k>
<l>line 12</l>
</level3>
<level4>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
<level4>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
<level21>
<d>line 214</d>
<e>line 215</e>
<f>line 216</f>
<g>line 217</g>
</level21>
<level2>
<d>line 19</d>
<e>line 20</e>
<f>line 21</f>
<g>line 22</g>
</level2>
<level3>
<h>line 23</h>
<i>line 24</i>
<j>line 25</j>
<k>line 26</k>
<l>line 27</l>
</level3>
<level4>
<m>line 28</m>
<n>line 29</n>
<o>line 30</o>
</level4>
<level4>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
<level21>
<d>line 224</d>
<e>line 225</e>
<f>line 226</f>
<g>line 227</g>
</level21>
必填结果XML
<?xml version="1.0" encoding="UTF-8"?>
<root>
<root1>1234</root1>
<root2>5678</root2>
<level1>
<a>line 1</a>
<b>line 2</b>
<c>line 3</c>
<level2>
<d>line 4</d>
<e>line 5</e>
<f>line 6</f>
<g>line 7</g>
<level3>
<SequenceCount>1</SequenceCount>
<h>line 8</h>
<i>line 9</i>
<j>line 10</j>
<k>line 11</k>
<l>line 12</l>
<level4>
<SequenceCount>1</SequenceCount>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
<level4>
<SequenceCount>2</SequenceCount>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
</level3>
</level2>
<level21>
<SequenceCount>2</SequenceCount>
<d>line 214</d>
<e>line 215</e>
<f>line 216</f>
<g>line 217</g>
</level21>
<level2>
<d>line 19</d>
<e>line 20</e>
<f>line 21</f>
<g>line 22</g>
<level3>
<SequenceCount>3</SequenceCount>
<h>line 23</h>
<i>line 24</i>
<j>line 25</j>
<k>line 26</k>
<l>line 27</l>
<level4>
<SequenceCount>1</SequenceCount>
<m>line 28</m>
<n>line 29</n>
<o>line 30</o>
</level4>
<level4>
<SequenceCount>2</SequenceCount>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
</level3>
</level2>
<level21>
<SequenceCount>4</SequenceCount>
<d>line 224</d>
<e>line 225</e>
<f>line 226</f>
<g>line 227</g>
</level21>
</level1>
</root>
我的XSL
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fn="fn" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="2.0"
exclude-result-prefixes="xs fn">
<xsl:output indent="yes" />
<xsl:template match="/">
<xsl:for-each-group select="*" group-starting-with="root">
<root>
<xsl:for-each-group select="*" group-starting-with="*[name(.)='level1']">
<xsl:choose>
<xsl:when test="name(.)='level1'">
<level1>
<xsl:apply-templates />
<xsl:for-each-group select="current-group()" group-starting-with="*[name(.)='level2']">
<xsl:choose>
<xsl:when test="name(.)='level2'">
<level2>
<xsl:apply-templates />
<xsl:for-each-group select="current-group()" group-starting-with="*[name(.)='level3']">
<xsl:choose>
<xsl:when test="name(.)='level3'">
<level3>
<xsl:element name="SequenceCount"><xsl:number count="level3|level21" level="any"/></xsl:element>
<xsl:apply-templates />
<xsl:for-each-group select="current-group()" group-starting-with="*[name(.)='level4']">
<xsl:choose>
<xsl:when test="name(.)='level4'">
<level4>
<xsl:element name="SequenceCount"><xsl:number value="position() - 1"/></xsl:element>
<xsl:apply-templates />
</level4>
</xsl:when>
</xsl:choose>
</xsl:for-each-group>
</level3>
</xsl:when>
</xsl:choose>
</xsl:for-each-group>
</level2>
</xsl:when>
</xsl:choose>
</xsl:for-each-group>
<xsl:for-each-group select="current-group()" group-starting-with="*[name(.)='level21']">
<xsl:choose>
<xsl:when test="name(.)='level21'">
<level21>
<xsl:element name="SequenceCount"><xsl:number count="level3|level21" level="any"/></xsl:element>
<xsl:apply-templates />
</level21>
</xsl:when>
</xsl:choose>
</xsl:for-each-group>
</level1>
</xsl:when>
</xsl:choose>
</xsl:for-each-group>
</root>
</xsl:for-each-group>
</xsl:template>
<xsl:template match="node()">
<xsl:copy>
<xsl:apply-templates select="node()" />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
当前输出XML
<?xml version="1.0" encoding="UTF-8"?>
<root>
<level1>
<a>line 1</a>
<b>line 2</b>
<c>line 3</c>
<level2>
<d>line 4</d>
<e>line 5</e>
<f>line 6</f>
<g>line 7</g>
<level3>
<SequenceCount>1</SequenceCount>
<h>line 8</h>
<i>line 9</i>
<j>line 10</j>
<k>line 11</k>
<l>line 12</l>
<level4>
<SequenceCount>1</SequenceCount>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
<level4>
<SequenceCount>2</SequenceCount>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
</level3>
</level2>
<level2>
<d>line 19</d>
<e>line 20</e>
<f>line 21</f>
<g>line 22</g>
<level3>
<SequenceCount>3</SequenceCount>
<h>line 23</h>
<i>line 24</i>
<j>line 25</j>
<k>line 26</k>
<l>line 27</l>
<level4>
<SequenceCount>1</SequenceCount>
<m>line 28</m>
<n>line 29</n>
<o>line 30</o>
</level4>
<level4>
<SequenceCount>2</SequenceCount>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
</level3>
</level2>
<level21>
<SequenceCount>2</SequenceCount>
<d>line 214</d>
<e>line 215</e>
<f>line 216</f>
<g>line 217</g>
</level21>
<level21>
<SequenceCount>4</SequenceCount>
<d>line 224</d>
<e>line 225</e>
<f>line 226</f>
<g>line 227</g>
</level21>
</level1>
</root>
答案 0 :(得分：0)
我认为以下样式表为您提供了所需的分组：
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:mf="http://example.com/mf"
exclude-result-prefixes="xs mf">
<xsl:output indent="yes"/>
<xsl:function name="mf:group" as="node()*">
<xsl:param name="elements" as="element()*"/>
<xsl:param name="level" as="xs:integer"/>
<xsl:for-each-group select="$elements" group-starting-with="*[starts-with(local-name(), concat('level', $level))]">
<xsl:choose>
<xsl:when test="self::*[starts-with(local-name(), concat('level', $level))]">
<xsl:copy>
<xsl:if test="$level = (3, 4)">
<SequenceCount><xsl:value-of select="position()"/></SequenceCount>
</xsl:if>
<xsl:apply-templates/>
<xsl:sequence select="mf:group(current-group() except ., $level + 1)"/>
</xsl:copy>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:function>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* , node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="root">
<xsl:copy>
<xsl:sequence select="mf:group(*, 1)"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
对于SequenceCount元素，某些值与发布的结果示例中的值相同，有些值不同，有些值丢失。让我们首先确定分组是否符合您的要求，然后我们可以尝试改进序列计数值。您可能希望以书面形式解释计数所指的内容。
[edit]根据您的XSLT代码，我添加了代码来计算不同级别的SequenceNumber，现在完整的样式表
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:mf="http://example.com/mf"
exclude-result-prefixes="xs mf">
<xsl:output indent="yes"/>
<xsl:function name="mf:group" as="node()*">
<xsl:param name="elements" as="element()*"/>
<xsl:param name="level" as="xs:integer"/>
<xsl:for-each-group select="$elements" group-starting-with="*[starts-with(local-name(), concat('level', $level))]">
<xsl:choose>
<xsl:when test="self::*[starts-with(local-name(), concat('level', $level))]">
<xsl:copy>
<xsl:choose>
<xsl:when test="self::level3">
<SequenceCount><xsl:number count="level3 | level21"/></SequenceCount>
</xsl:when>
<xsl:when test="self::level4">
<SequenceCount><xsl:value-of select="position()"/></SequenceCount>
</xsl:when>
<xsl:when test="self::level21">
<SequenceCount><xsl:number count="level3|level21"/></SequenceCount>
</xsl:when>
</xsl:choose>
<xsl:apply-templates/>
<xsl:sequence select="mf:group(current-group() except ., $level + 1)"/>
</xsl:copy>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:function>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* , node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="root">
<xsl:copy>
<xsl:sequence select="mf:group(*, 1)"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
使用Saxon作为输入
<root>
<root1>1234</root1>
<root2>5678</root2>
<level1>
<a>line 1</a>
<b>line 2</b>
<c>line 3</c>
</level1>
<level2>
<d>line 4</d>
<e>line 5</e>
<f>line 6</f>
<g>line 7</g>
</level2>
<level3>
<h>line 8</h>
<i>line 9</i>
<j>line 10</j>
<k>line 11</k>
<l>line 12</l>
</level3>
<level4>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
<level4>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
<level21>
<d>line 214</d>
<e>line 215</e>
<f>line 216</f>
<g>line 217</g>
</level21>
<level2>
<d>line 19</d>
<e>line 20</e>
<f>line 21</f>
<g>line 22</g>
</level2>
<level3>
<h>line 23</h>
<i>line 24</i>
<j>line 25</j>
<k>line 26</k>
<l>line 27</l>
</level3>
<level4>
<m>line 28</m>
<n>line 29</n>
<o>line 30</o>
</level4>
<level4>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
<level21>
<d>line 224</d>
<e>line 225</e>
<f>line 226</f>
<g>line 227</g>
</level21>
</root>
我得到了结果
<root>
<root1>1234</root1>
<root2>5678</root2>
<level1>
<a>line 1</a>
<b>line 2</b>
<c>line 3</c>
<level2>
<d>line 4</d>
<e>line 5</e>
<f>line 6</f>
<g>line 7</g>
<level3>
<SequenceCount>1</SequenceCount>
<h>line 8</h>
<i>line 9</i>
<j>line 10</j>
<k>line 11</k>
<l>line 12</l>
<level4>
<SequenceCount>1</SequenceCount>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
<level4>
<SequenceCount>2</SequenceCount>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
</level3>
</level2>
<level21>
<SequenceCount>2</SequenceCount>
<d>line 214</d>
<e>line 215</e>
<f>line 216</f>
<g>line 217</g>
</level21>
<level2>
<d>line 19</d>
<e>line 20</e>
<f>line 21</f>
<g>line 22</g>
<level3>
<SequenceCount>3</SequenceCount>
<h>line 23</h>
<i>line 24</i>
<j>line 25</j>
<k>line 26</k>
<l>line 27</l>
<level4>
<SequenceCount>1</SequenceCount>
<m>line 28</m>
<n>line 29</n>
<o>line 30</o>
</level4>
<level4>
<SequenceCount>2</SequenceCount>
<m>line 13</m>
<n>line 14</n>
<o>line 15</o>
</level4>
</level3>
</level2>
<level21>
<SequenceCount>4</SequenceCount>
<d>line 224</d>
<e>line 225</e>
<f>line 226</f>
<g>line 227</g>
</level21>
</level1>
</root>