Question

对于队列分析的需要，我试图让每个客户的下一步行动（取消订阅，升级，降级......）

我有一个包含以下数据的快照：

customer | month      | last_action   | last_action_date
1          01-01-2012   subscription    01-01-2012
1          02-01-2012   subscription    01-01-2012
1          03-01-2012   subscription    01-01-2012
1          04-01-2012   downgrade       04-01-2012
1          05-01-2012   downgrade       04-01-2012
1          06-01-2012   downgrade       04-01-2012
1          07-01-2012   unsubscription  07-01-2012

正如您所看到的，该行动仅在完成月份时才知道，在01-01-2012月我们还不知道客户在04-01-2012期间降级，因此我们无法分析他的使用行为相对于他的降级月份。取消订阅也是一样。

所需的数据集如下：

customer | month      | downgrade_date   | unsubscription_date
1          01-01-2012   04-01-2012         07-01-2012
1          02-01-2012   04-01-2012         07-01-2012
1          03-01-2012   04-01-2012         07-01-2012
1          04-01-2012   12-31-9999         07-01-2012
1          05-01-2012   12-31-9999         07-01-2012
1          06-01-2012   12-31-9999         07-01-2012
1          07-01-2012   12-31-9999         07-01-2012

我可以轻松地使用last_value分析函数取消订阅日期，但没有找到获得降级日期的方法。

这是我的SQL查询：

SELECT month_id, 
       customer_id,
       CASE 
         WHEN LAST_VALUE(last_action) OVER (PARTITION BY customer_id ORDER BY month_id RANGE BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING) = 'unsubscription' THEN LAST_VALUE(last_action_date) OVER (PARTITION BY customer_id ORDER BY month_id RANGE BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING)    
         ELSE TO_DATE('99991231', 'yyyymmdd')
       END unsubscription_date
FROM my_table
;

任何获取“下一个”操作日期的方法，例如“downgrade_date”。

我正在使用Oracle。

Answer 1

在oracle 11中，您可以使用lead()和ignore nulls选项执行此操作：

select customer, MONTH,
       lead(case when last_action = 'downgrade' then last_action_date end ignore nulls) over
                 (partition by customer order by month desc) as downgrade_date,
       lead(case when last_action = 'unsubscription' then last_action_date end ignore nulls) over
                 (partition by customer order by month desc) as downgrade_date,
from my_table t

如果您没有ignore nulls，则可以使用min()执行类似操作：

select customer, MONTH,
       min(case when last_action = 'downgrade' then last_action_date end) over
                (partition by customer order by month range between current and unbounded following
                ) as downgrade_date,
       min(case when last_action = 'unsubscription' then last_action_date end) over
                (partition by customer order by month range between current and unbounded following
                ) as unsubscription_date
from my_table t

使用分析函数的下一步操作

1 个答案: