Question

我创建了一个编号为1-10的名字列表。我希望用户能够输入数字（1-10）来选择名称。我有以下代码，但仍然无法让它工作。我是python的新手。谢谢你的帮助

def taskFour():

    1 == Karratha_Aero
    2 == Dampier_Salt
    3 == Karratha_Station
    4 == Roebourne_Aero
    5 == Roebourne
    6 == Cossack
    7 == Warambie
    8 == Pyramid_Station
    9 == Eramurra_Pool
    10 == Sherlock


    print''
    print 'Choose a Base Weather Station'
    print 'Enter the corresponding station number'
    selection = int(raw_input('Enter a number from: 1 to 10'))
    if selection == 1:
        selectionOne()
    elif selection == 2:
        selectionTwo()
    elif selection == 3:
        selectionThree()

Answer 1

您正在遵循反模式。当有一百万个不同的电台或每个电台有多个数据时你打算做什么？

您无法手动selectionOne()完成selectionOneMillion()。

这样的事情怎么样：

stations = {'1': "Karratha_Aero",
            '2': "Karratha_Station",
            '10': "Sherlock"}

user_selection = raw_input("Choose number: ")

print stations.get(user_selection) or "No such station"

输入/输出：

1 => Karratha_Aero
10 => Sherlock
5 => No such station

Answer 2

首先，你需要一个真实的清单。您当前拥有的内容（1 == Name）既不是列表，也不是有效语法（除非您在每个名称后面都有变量）。将您的列表更改为：

names = ['Karratha_Aero', 'Dampier_Salt', 'Karratha_Station', 'Roebourne_Aero', 'Roebourne', 'Cossack', 'Warambie', 'Pyramid_Station', 'Eramurra_Pool', 'Sherlock']

然后，将底部代码更改为：

try:
  selection = int(raw_input('Enter a number from: 1 to 10'))
except ValueError:
  print "Please enter a valid number. Abort."
  exit
selection = names[selection - 1]

然后

selection将成为用户选择的名称。

Answer 3

以下是适合您的工作代码：

def taskFour():
    myDictionary={'1':'Name1','2':'Name2','3':'Name3'}
    print''
    print 'Choose a Base Weather Station'
    print 'Enter the corresponding station number'
    selection = str(raw_input('Enter a number from: 1 to 10'))
    if selection in myDictionary:
        print myDictionary[selection]
        #Call your function with this name "selection" instead of print myDictionary[selection] 

taskFour()

从python列表中选择一个项目

3 个答案: