转换为SAS时间

时间:2013-04-30 12:13:19

标签: sas

我有一个包含时间的txt文件,格式为161058.262,目的是16:10:58.262。

我找不到将此值转换为正确的SAS数字时间值的INFORMAT。 TIME12.3将转换为数字。它存储为579824520,并使用格式TOD12.3格式显示为22:22:00.000

有什么建议吗?

由于 丹

3 个答案:

答案 0 :(得分:5)

我会做一个快速转型,使现有的信息工作。例如,您的格式与B8601TM期望的格式相同,除了分隔秒的小数点的点。您可以从字符串中删除点,然后应用信息。

示例:

data test;
    input t $10.;

    format tt TOD12.3;

    tt = inputn(compress(t, , "kn"),  "B8601TM9.3");

datalines;
161058.262
; run;

答案 1 :(得分:1)

我不知道具体的信息,但你当然可以在冒号工作,或者做数学计算以使其成为使用HMS的时间。

data test;
informat t_pre $10.;
input t_pre $;
t = input(catx(':',substr(t_pre,1,2),substr(t_pre,3,2),substr(t_pre,5)),TIME12.3);
*CATX concatenates using a delimiter, so this generates a string like 16:10:58.262;
*Then converts to TIME12.3;
put t= TIME12.3 t_pre=;
datalines;
161058.262
;;;;
run;

data test;
input t_pre;
t = hms(floor(t_pre/10000),floor(mod(t_pre,10000)/100),mod(t_pre,100));
*HMS generates a time value from hours, minutes, seconds, and allows milliseconds in the seconds;
*So we use combination of division and modulo to separate the number into component parts;
put t= TIME12.3;
datalines;
161058.262
;;;;
run;

答案 2 :(得分:1)

data _null_;
    input int_val $10.;
    format time_val timeampm15.3;
    time_val = input(
                 prxchange('s/(\d?\d)(\d\d)(\d\d\.\d\d\d)/$1:$2:$3/',
                          -1, int_val),
                 time10.3);
    put int_val
    @15 time_val timeampm15.3
    @30 time_val 10.3;
datalines;
000000.001
012345.678
12345.678
161058.262
235959.999
run;

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000000.001    12:00:00.000 AM     0.000
012345.678     1:23:45.600 AM  5025.600
12345.678      1:23:45.670 AM  5025.670
161058.262     4:10:58.200 PM 58258.200
235959.999    11:59:59.900 PM 86399.900
NOTE: DATA statement used (Total process time):
      real time           0.01 seconds
      cpu time            0.01 seconds