从文件中删除多行字符串

时间:2013-04-30 04:10:19

标签: windows batch-file

我正在尝试使用Windows中的Batch从文件中删除多行字符串。我的批处理代码正在做一些奇怪的事情,例如将字符串ECHO is off.放在文件中。

编辑:包含所有代码
如何从代码中删除多行字符串?

@echo off &setlocal enabledelayedexpansion

Rem Read file and store all contents in string
Set replace=
Set target=
Set infile=usermenuTest1.4d
Rem %~1
Set outfile=usermenuTest2.4d
Rem %~2

for /f "delims=" %%i in (%infile%) do set "target=!target! %%i"
echo %target%

Rem Remove the target string from myOtherFile.txt: this code is from http://stackoverflow.com/questions/5273937/how-to-replace-substrings-in-windows-batch-file
@echo off & setlocal enabledelayedexpansion
for /f "tokens=1,* delims=¶" %%A in ( 'type "%outfile%"') do SET "string=%%A"
SET "modified=!string:%target%=%replace%!"
(echo(%modified%)>> "%outfile%"

我要替换的多行字符串示例:

Menu "User" {
   Button "" {
      Walk_Right ""
   }
}

Menu "" {
   // Button "CAD" {
   //   Walk_Right "CAD"    
   //   }
    Button "Design" {
      Walk_Right "Design"    
      }
    Button "Services" {
      Walk_Right "Services"        
      }
    Button "Strings" {
      Walk_Right "Strings"        
      }
    Button "Survey" {
      Walk_Right "Survey"        
      }
    Button "Utilities" {
            Walk_Right "Utilities"        
      }
    Button "Zoom" {
      Walk_Right "Zoom"        
      }        
  }

1 个答案:

答案 0 :(得分:0)

试试这个:

@echo off & setlocal enabledelayedexpansion
for /f "tokens=1,* delims=¶" %%A in ( 'type "%outfile%"') do SET "string=%%A"
SET "modified=!string:%target%=%replace%!"
(echo(%modified%)>> "%outfile%"