Question

嗨'我要在我的博客网址中将Id和slug的混合物应用为网址

http://stackoverflow.com/questions/16286556/using-httpclient-to-log-in-to-hpps-server

要做到这一点，我在global.asax

中定义了这个Url

  routes.MapRoute("IdSlugRoute", "{controller}/{action}/{id}/{slug}",
                            new {controller = "Blog", action = "Post", id = UrlParameter.Optional,slug=""});

但是当我运行我的应用程序时，Url看起来像这样：

http://localhost:1245/Blog/Post?postId=dd1140ce-ae5e-4003-8090-8d9fbe253e85&slug=finally-i-could-do-solve-it

我不想要那些？和=在网址中！我只是想用斜线将它们分开我该怎么办呢？

回复此Url的actionresult是这样的：

 public ActionResult Post(Guid postId,string slug)
        {
            var post = _blogRepository.GetPostById(postId);
            return View("Post",post);
        }

Answer 1

确保您的自定义路线超出默认路线。它将停在它找到的第一条匹配路线上。

Answer 2

更改路线以使用postId而不是Id

routes.MapRoute("IdSlugRoute", "{controller}/{action}/{postId}/{slug}",
                            new {controller = "Blog", action = "Post", postId = UrlParameter.Optional,slug=""});

Answer 3

您是否尝试将postId和slug设置为UrlParameter.Optional？ routes.MapRoute("IdSlugRoute", "{controller}/{action}/{postId}/{slug}", new {controller = "Blog", action = "Post", postId = UrlParameter.Optional,slug=UrlParameter.Optional});

修改

我让这个在当地工作。我得到的是一个模型：

public class HomeViewModel { public Guid PostID { get; set; } public string Slug { get; set; } }

一个有两个动作的控制器：

public class HomeController : Controller { public ActionResult Index() { Guid guid = Guid.NewGuid(); var model = new HomeViewModel { PostID = guid, Slug = "this-is-a-test" }; return View(model); } public ActionResult Post(Guid postID, string slug) { // get the post based on postID } }

带有actionlink的视图：

@model MvcApplication1.Models.HomeViewModel @{ ViewBag.Title = "Home Page"; } @Html.ActionLink("Click me!", "Post", new { postId = Model.PostID, slug = Model.Slug})

为了使路由工作，我必须在默认路由之前对路由进行硬编码：

public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute("IdSlugRoute", "Home/Post/{postID}/{slug}", new { controller = "Home", action = "Post", postID = Guid.Empty, slug = UrlParameter.Optional }); routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = UrlParameter.Optional } // Parameter defaults ); }

自定义MVC URL路由显示Id和Url Slug的混合

3 个答案: