我们有一个项目要求我们编写一个程序，允许用户输入一系列数字“将数字读入数组进行进一步处理，用户通过输入负数来表示完成它们（负数不用于在读完所有数字之后，执行以下操作，总结输入的＃，计算输入的＃，找到输入的最小/最大＃，计算平均值，然后在屏幕上输出它们。所以工作版本我所做的就是这样
/* Reads data into array.
paramater a = the array to fill
paramater a_capacity = maximum size
paramater a_size = filled with size of a after reading input. */
void read_data(double a[], int a_capacity, int& a_size)
{
a_size = 0;
bool computation = true;
while (computation)
{
double x;
cin >> x;
if (x < 0)
computation = false;
else if (a_size == a_capacity)
{
cout << "Extra data ignored\n";
computation = false;
}
else
{
a[a_size] = x;
a_size++;
}
}
}
/* computes the maximum value in array
paramater a = the array
Paramater a_size = the number of values in a */
double largest_value(const double a[], int a_size)
{
if(a_size < 0)
return 0;
double maximum = a[0];
for(int i = 1; i < a_size; i++)
if (a[i] > maximum)
maximum = a[i];
return maximum;
}
/* computes the minimum value in array */
double smallest_value(const double a[], int a_size)
{
if(a_size < 0)
return 0;
double minimum = a[0];
for(int i = 1; i < a_size; i++)
if (a[i] < minimum)
minimum = a[i];
return minimum;
}
//computes the sum of the numbers entered
double sum_value(const double a [], int a_size)
{
if (a_size < 0)
return 0;
double sum = 0;
for(int i = 0; i < a_size; i++)
sum = sum + a[i];
return sum;
}
//keeps running count of numbers entered
double count_value(const double a[], int a_size)
{
if (a_size < 0)
return 0;
int count = 0;
for(int i = 1; i <= a_size; i++)
count = i;
return count;
}
int _tmain(int argc, _TCHAR* argv[])
{
const int INPUT_CAPACITY = 100;
double user_input[INPUT_CAPACITY];
int input_size = 0;
double average = 0;
cout << "Enter numbers. Input negative to quit.:\n";
read_data(user_input, INPUT_CAPACITY, input_size);
double max_output = largest_value(user_input, input_size);
cout << "The maximum value entered was " << max_output << "\n";
double min_output = smallest_value(user_input, input_size);
cout << "The lowest value entered was " << min_output << "\n";
double sum_output = sum_value(user_input, input_size);
cout << "The sum of the value's entered is " << sum_output << "\n";
double count_output = count_value(user_input, input_size);
cout << "You entered " << count_output << " numbers." << "\n";
cout << "The average of your numbers is " << sum_output / count_output << "\n";
string str;
getline(cin,str);
getline(cin,str);
return 0;
}
这很好，我现在遇到的问题是第2部分。我们要“将数组复制到另一个并通过N个元素移动数组”。我不知道从哪里开始。我已经查找了一些关于复制数组的资源，但我不知道如何在我完成的当前代码中实现它们，特别是在转移方面。如果任何人有任何想法，想法或资源可以帮助我走上正确的道路，那将非常感激。我也应该指出，我是一个初学者（这是一个初学者课程），所以这个任务可能不是“最佳”方式可以完成的事情，而是包含了我们学到的东西，如果这是有意义的。
答案 0 :(得分：2)
for(int i = 0; i < n; ++i){
int j = (i - k)%n;
b[i] = a[j];
}
检查一下。我不确定 如果这有效，你可以改进它
for(int i = 0; i < n; ++i)
b[i] = a[(i - k)%n];//here can be (i +/- k) it depends which direction u would shift
答案 1 :(得分：0)
如果您只想将数组复制到另一个数组并移位它们
ex：input = 1,2,3,4,5;输出= 3,4,5,1,2
麻烦的解决方案是
//no template or unsafe void* since you are a beginner
int* copy_to(int *begin, int *end, int *result)
{
while(begin != end){
*result = *begin;
++result; ++begin;
}
return result;
}
int main()
{
int input[] = {1, 2, 3, 4, 5};
size_t const size = sizeof(input) / sizeof(int);
size_t const begin = 2;
int output[size] = {0}; //0, 0, 0, 0, 0
int *result = copy_to(input + begin, input + size - begin, output); //3, 4, 5, 0, 0
copy_to(input, input + begin, result); //3, 4, 5, 1, 2
return 0;
}
stl算法集如何帮助我们？
read_data保持与您提供的相同
#include <algorithm> //std::minmax_element, std::rotate_copy
#include <iostream>
#include <iterator> //for std::begin()
#include <numeric> //for std::accumulate()
#include <string>
#include <vector>
int main(int argc, char *argv[]) //don't use _tmain, they are unportable
{
const int INPUT_CAPACITY = 100;
double user_input[INPUT_CAPACITY];
int input_size = 0;
double average = 0;
cout << "Enter numbers. Input negative to quit.:\n";
read_data(user_input, INPUT_CAPACITY, input_size);
auto const min_max = std::minmax_element (user_input, user_input + input_size); //only valid for c++11
std::cout << "The maximum value entered was " << min_max.second << "\n";
std::cout << "The lowest value entered was " << min_max.first << "\n";
double sum_output = std::accumulate(user_input, user_input + input_size, 0);
cout << "The sum of the value's entered is " << sum_output << "\n";
//I don't know the meaning of you count_value, why don't just output input_size?
double count_output = count_value(user_input, input_size);
cout << "You entered " << count_output << " numbers." << "\n";
cout << "The average of your numbers is " << sum_output / count_output << "\n";
int shift;
std::cout<<"How many positions do you want to shift?"<<std::endl;
std::cin>>shift;
std::vector<int> shift_array(input_size);
std::rotate_copy(user_input, user_input + shift, user_input + input_size, std::begin(shift_array));
//don't know what are they for?
std::string str;
std::getline(std::cin,str);
std::getline(std::cin,str);
return 0;
}
如果您的编译器还不支持c ++ 11功能
std :: minmax_element可以替换为 std :: min_element和std :: max_element std :: begin（）可以替换为shift_array.begin（）
我不知道你们班级的教学风格是什么，在我的拙见中，初学者应该这样做 从c ++提供的那些更高级别的组件开始，如vector，string，algorithms 我想你的老师就是这样教你的，你可以使用 算法和容器都附带了c ++（让我们恳求你的班级不是教你“带课程”，并说“OOP是世界上最好的东西”）。
ps：如果你愿意，可以使用vector来替换原始数组