Question

我是php的新手。用这个试验了很多。我写了另一个代码。但它在第26行显示错误。我无法找到问题。请检查一下，告诉我问题是什么。的 result.php

    <?php
if (isset ($_POST["name"])){
    $name=$_POST["name"];
}
if(isset ($_POST["yob"])){
    $yob=(int) $_POST["yob"];
}
if(isset ($_POST["wifename"])){
    $wifename=$_POST["wifename"];
}
if(isset ($_POST["wyob"])){
    $wyob= (int) $_POST["wyob"];
}
$currentyear=date("Y");
if($yob>=$currentyear){
    echo "Sorry {$name} you have not born yet.";
}
if($currentyear>$yob){
    $husbandage=$currentyear-$yob;
}
if($wyob>=$currentyear){
    echo "Sorry {$name} your mother in law is still virgin.";
}
else{$wifeage=$currentyear-$wyob;}
if($husbandage>$wifeage){
    echo "You are {"$husbandage-$wifeage"} years older than your wife";
}
if($husbandage<$wifeage){
    echo "You are {$wifeage-$husbandage} years older than your wife";}
    if($husbandage==$wifeage){
        echo "You and your wife are same age";}

?>

agecalculator.php

<html>
<title>Age Difference Calculator</title>
<body>
<form action="result.php" type="post">
    Your Name: <input type="text" name= "name"><br/>
    Year Of Birth: <input type= "text" name:"yob"><br/>
    Your Wife's Name: <input type="text" name="wifename"><br/>
    Your Wife's Year Of Birth: <input type="text" name="wyob"><br/>
    <input type="submit">
</form> 
</body>
</html>

Answer 1

问题是

{int}

应该是

(int)

Answer 2

也许你应该改变

$yob={int} $_POST["yob"];

为此：

$yob=(int) $_POST["yob"];

无法在第6行找到错误

2 个答案: