通过执行存储过程,我有一个动态DataTable:
A B C D
1 0 0 1
0 0 0 1
1 1 0 1
如何根据每列的总和按降序排序?我想要它:
D A B C
1 1 0 0
1 0 0 0
1 1 1 0
我创建了一个List来存储每列的总和:
List<Column> temptArray;
public class Column
{
public int columnIndex;
public int count;
}
我计算总和
private void calculateSum()
{
temptArray= new List<Column>();
for (int column = 0; column <= dataTable.Columns.Count -1; column++)
temptArray.Add(new Column{ columnIndex = column });
for (int row = 0; row <= dataTable.Rows.Count - 1; row++)
for (int column = 0; column <= dataTable.Columns.Count - 1; column++)
temptArray[column].count+= (int)dataTable.Rows[row].ItemArray.GetValue(column);
}
它工作正常。
然后我对我的诱惑进行排序:
temptArray = temptArray.OrderByDescending(x => x.count).ToList();
我的temptArray现在应该订购:DABC
如何像temptArray一样更改DataTable顺序?
答案 0 :(得分:1)
尝试使用DataColumn.SetOrdinal方法。例如:
dataTable.Columns["D"].SetOrdinal(0);
dataTable.Columns["A"].SetOrdinal(1);
dataTable.Columns["B"].SetOrdinal(2);
dataTable.Columns["C"].SetOrdinal(3);
以下是示例代码:
// this is sample C# console application
using System.Data;
using System.Linq;
namespace SO
{
class Program
{
static void Main(string[] args)
{
DataTable dt = GetTable();
// get list of Data Table column names like A, B, C, D...
var columnNames = (from DataColumn col in dt.Columns
select col.ColumnName).ToList();
// compute sum for each column and get list of objects which having sum and column name as property.
var computed = columnNames.Select(c => new { ColumnName = c, Sum = dt.Compute(string.Format("Sum({0})", c), "") }).OrderByDescending(p => p.Sum).ToList();
// set the column position based on Sum of the column
for (int i = 0; i < computed.Count(); i++)
{
dt.Columns[computed[i].ColumnName].SetOrdinal(i);
}
}
// testing I have added this method to create Data Table with testing data
static DataTable GetTable()
{
DataTable table = new DataTable();
table.Columns.Add("A", typeof(int));
table.Columns.Add("B", typeof(int));
table.Columns.Add("C", typeof(int));
table.Columns.Add("D", typeof(int));
table.Rows.Add(1, 0, 0, 1);
table.Rows.Add(0, 0, 0, 1);
table.Rows.Add(1, 1, 0, 1);
return table;
}
}
}