Question

您好我正在尝试将变量$地址回显到Google地图网址中：

<iframe width="640" height="480" frameborder="0" scrolling="no" marginheight="0" marginwidth="0" src="https://maps.google.it/maps?q=<?php echo $address; ?>&output=embed"></iframe>

我无法让变量在<?php echo $address; ?>

中回显

这是我的分页剧本，（我已经知道了）。

这是我想要将地址回显到url中的相同脚本，因此每当有人搜索地址时，它会自动生成静态地图。

<?php 



 // Connects to your Database 

 mysql_connect("xxx", "xxx", "xxx") or die(mysql_error()); 

 mysql_select_db("xxx") or die(mysql_error()); 
error_reporting(0);

 //This checks to see if there is a page number. If not, it will set it to page 1 

 if (!(isset($pagenum))) 

 { 

 $pagenum = 1; 

 } 



 //Here we count the number of results 

 //Edit $data to be your query 

 $data = mysql_query("SELECT * FROM bus WHERE fname 
LIKE '%" . mysql_real_escape_string($name)      . "%' AND Address
LIKE '%" . mysql_real_escape_string($address)       . "%' City
LIKE '%" . mysql_real_escape_string($city)      . "%' AND state
LIKE '%" . mysql_real_escape_string($state)         . "%' AND zip
LIKE '%" . mysql_real_escape_string($zip)   . "%' AND phone
LIKE '%" . mysql_real_escape_string($phone)     . "%' AND hours
LIKE '%" . mysql_real_escape_string($hours)     . "%'") or die(mysql_error()); 

 $rows = mysql_num_rows($data); 



 //This is the number of results displayed per page 

 $page_rows = 10; 



 //This tells us the page number of our last page 

 $last = ceil($rows/$page_rows); 



 //this makes sure the page number isn't below one, or more than our maximum pages 

if ($pagenum > $last) {
    $pagenum = $last;
}
if ($pagenum < 1) {
    $pagenum = 1;
}



 //This sets the range to display in our query 

$max = 'limit ' .((($pagenum == 0) ? 1 : $pagenum) - 1) * $page_rows .',' .$page_rows; 

 //This is your query again, the same one... the only difference is we add $max into it

 $data_p = mysql_query("SELECT * FROM bus WHERE fname 
LIKE '%" . mysql_real_escape_string($name)      . "%' AND Address
LIKE '%" . mysql_real_escape_string($address)       . "%' City
LIKE '%" . mysql_real_escape_string($city)      . "%' AND state
LIKE '%" . mysql_real_escape_string($state)         . "%' AND zip
LIKE '%" . mysql_real_escape_string($zip)   . "%' AND phone
LIKE '%" . mysql_real_escape_string($phone)     . "%' AND hours
LIKE '%" . mysql_real_escape_string($hours)     . "%' $max") or die(mysql_error()); 


 //This is where you display your query results

 while($info = mysql_fetch_array( $data_p )) 
{
 echo "<hr width=500><table  width=500><td id=table1><br>Business Name:&nbsp;"; 
 echo $info['fname'];
 echo "<br>Address:&nbsp;"; 
 echo $info['Address']; 
 echo "<br>City:&nbsp;"; 
 echo $info['City']; 
 echo "<br>State:&nbsp;"; 
 echo $info['state']; 
 echo "<br>Zip Code:&nbsp;"; 
 echo $info['zip']; 
 echo "<br>Phone:&nbsp;"; 
  echo $info['phone']; 
 echo "<br>Hours:&nbsp;"; 
 echo $info['hours']; 
 echo "<br></td></table><hr width=500>";
}


 // This shows the user what page they are on, and the total number of pages

 echo " --Page $pagenum of $last-- <p>";


 // First we check if we are on page one. If we are then we don't need a link to the previous page or the first page so we do nothing. If we aren't then we generate links to the first page, and to the previous page.

 if ($pagenum == 1) 

 {

 } 

 else 

 {

 echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=1'> <<-First</a> ";

 echo " ";

 $previous = $pagenum-1;

 echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$previous'> <-Previous</a> ";

 } 


 //just a spacer

 echo " ---- ";


 //This does the same as above, only checking if we are on the last page, and then generating the Next and Last links

 if ($pagenum == $last) 

 {

 } 

 else {

 $next = $pagenum+1;

 echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$next'>Next -></a> ";

 echo " ";

 echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$last'>Last -></a> ";

 } 

 ?> 
 <?php

 ?>
 <?php
  //This counts the number or results - and if there wasn't any it gives them a little message explaining that 
 $anymatches=mysql_num_rows($data_p); 
 if ($anymatches == 0) 
 { 
 echo "Sorry, but we can not find an entry to match your query<br><br>"; 
 } 
 //And we remind them what they searched for 
 echo "<b>Searched For:
        </b> " .$fname; 


 ?>

Answer 1

从php 4.0开始，您需要使用$_POST['field_name']来定位帖子中的字段。因此，您需要将其更改为$_POST['address']。

Answer 2

由于Google地图的地址可以是完整地址（拉链，门牌号码，街道，区域，城镇，地区，州，国家等），也可能是这些方法的任何组合，您的方法是错误的。

您应该决定所需的元素，并为每个元素分别输入。然后，您可以从这些

建立搜索地址

Echo $ address变量进入google map url参数

2 个答案: