Question

我正在尝试创建一个查询，其中第一个查询将返回COLUMN，根据第一个查询的结果将执行第二个查询：

SELECT OBJECT_ID from test.CORRELATION_SET
WHERE (NAME='STATUS' AND VALUE ='SUCCESS')

|OBJECT_ID|
|---------|
|A        |
|B        |
|C        |
|---------|

SELECT * FROM test.CORRELATION_SET
WHERE OBJECT_ID = ('A'|'B'|'C');

Answer 1

以下是查询

SELECT * FROM CORRELATION_SET
WHERE OBJECT_ID in (
  SELECT OBJECT_ID from CORRELATION_SET
  WHERE (NAME='STATUS' AND VALUE ='SUCCESS')
)

Answer 2

你的例子没有意义，看起来你错过了在第二个查询中命名的表。

SELECT * from test.CORRELATION_SET WHERE (NAME='STATUS' AND VALUE ='SUCCESS')

上述查询将返回与两个查询相同的结果。假设您的第二个查询使用了一个名为CORRELATION_SET2的表，您可以使用Kumar在其评论中使用的嵌套查询。您也可以使用联接。

SELECT set2.* FROM test.CORRELATION_SET set1
    JOIN test.CORRELATION_SET2 set2 ON set2.object_id = set1.object_id
WHERE
  set1.name = 'status' and set1.value = 'success';

使用多种搜索功能编写查询？

2 个答案: