Question

我已经为我的网站开发了一个排名系统，其中为每个项目分配排名以沿着选择（向上和向下）移动它。它工作正常。

但问题是如果删除了一条记录，则旁边的记录将不会再次排名。但其他人工作正常。

实施例

id | cat name | Rank
 1 | Jackets  | 1
 2 | T-shirts | 2
 3 | Gloves   | 3*
 4 | Scarf    | 4

如果我删除第三行（哪个是手套）上排（夹克和T恤工作正常）同样下来的话。但围巾的排名功能现在将停止......

任何人都可以提供简单的解决方案来解决这个问题。

以下是代码........

//============================  UP    ================================//
if(isset($_REQUEST["up"])) {

   $a=$_REQUEST["up"];
   //echo $a; die();
   if($a>1){
        $b=$a - 1 ;

        $id=$_REQUEST["id"];
        //echo $id; die();

        $sql =mysql_query("SELECT * FROM scat WHERE rank ='".$b."'");

        while ($rc= mysql_fetch_array($sql)){
            $c=$rc["sid"];
            $count=mysql_num_rows($sql);

            if($count == 1){

                // update item with already placed id
                $d=mysql_query("update scat set rank='".$a."' where sid='".$c."'");

                // Update up Item 
                $qry=mysql_query("update scat set rank='".$b."' where sid='".$id."' ");

                //header('location:main.php'); break;
            }
        }
    }
}

//============================  Down    ================================//
if(isset($_REQUEST["dwn"])) {

   $a=$_REQUEST["dwn"];
   //echo $a;
   if($a>0) {
        $b=$a + 1 ;

        $id=$_REQUEST["id"];
        //echo $id;die();

        $sql =mysql_query("SELECT * FROM scat WHERE rank='".$b."'");

        while ($rc= mysql_fetch_array($sql)){
            $c=$rc["sid"];

            $count=mysql_num_rows($sql);

            if($count == 1){

                // update item with already placed id
                $d=mysql_query("update scat set rank='".$b."' where sid='".$id."'");

                // Update up Item 
                $qry=mysql_query("update scat set rank='".$a."' where sid='".$c."' ");

                //header('location:main.php'); break;
            }
        }
    }
}

桌子到了......

<table width="600" border="0" cellspacing="1" cellpadding="0" bgcolor="#007ba4">
    <tr>
        <td width="50" align="center" valign="top" bgcolor="#FFF" class="ver_nav">Id</td>
        <td width="350" align="center" valign="top" bgcolor="#FFF" class="ver_nav">Sub Cataagery name</td>
        <td colspan="2" align="center" valign="top" bgcolor="#FFF" class="ver_nav">Rank</td>
        <td width="75" align="center" valign="top" bgcolor="#FFF" class="ver_nav">Feature</td>
        <td width="75" align="center" valign="top" bgcolor="#FFF" class="ver_nav">Edit</td>
        <td width="75" align="center" valign="top" bgcolor="#FFF" class="ver_nav">Del</td>
    </tr>
    <?php $qry=mysql_query( "SELECT * FROM scat WHERE fid='".$_REQUEST[ "fid"]. "' order by rank "); while ($rc=mysql_fetch_array($qry)){ ?>
    <tr>
        <td width="50" align="center" valign="top" bgcolor="#FFF" class="cat">
            <?php echo $rc[ "rank"];?>
        </td>
        <td width="350" align="center" valign="top" bgcolor="#FFF"><a href="add_pimg.php?fid=<?php echo $rc[" fid "];?>&sid=<?php echo $rc["sid "];?>" class="cat"><?php echo $rc["scat"];?></a></td>
        <td width="75" align="center" valign="top" bgcolor="#FFF"> <a href="add_second_cat.php?fid=<?php echo $rc[" fid "];?>&up=<?php echo $rc["rank "];?>&id=<?php echo $rc["sid "];?>" class="cat">Up</a></td>
        <td width="75" align="center" valign="top" bgcolor="#FFF"> <a href="add_second_cat.php?fid=<?php echo $rc[" fid "];?>&dwn=<?php echo $rc["rank "];?>&id=<?php echo $rc["sid "];?>"class="cat">Down</a></td>
        <td width="75" align="center" valign="top" bgcolor="#FFF"> <a href="add_second_cat.php?fid=<?php echo $rc[" fid "];?>&feature=<?php echo $rc["rank "];?>&id=<?php echo $rc["sid "];?>" class="cat"><?php echo $rc["feature"];?></a></td>
        <td width="75" align="center" valign="top" bgcolor="#FFF"><a href="edit_scat.php?fid=<?php echo $rc[" fid "];?>&amp;sid=<?php echo $rc["sid "];?>" class="cat">Edit</a><a href="dell_scat.php?fid=<?php echo $rc[" fid "];?>&amp;sid=<?php echo $rc["sid "];?>" class="cat"></a></td>
        <td width="75" align="center" valign="top" bgcolor="#FFF"><a href="dell_scat.php?fid=<?php echo $rc[" fid "];?>&amp;sid=<?php echo $rc["sid "];?>" class="cat">Dell</a></td>
    </tr>
<?php }?>
</table>

Answer 1

您需要选择要交换的ID，而不是计算

这是我可怕的旧项目的代码。现在看起来很有趣

  if (isset($_POST['move'])) {
    $id=intval($_POST['move']);
    $place=db("SELECT place FROM $table WHERE id=$id");
    if (!$id OR !$place) die("id or place is not set");

    if (isset($_POST['up'])) {
      $sort=db("SELECT sort FROM $table WHERE id=$id");
      $sort2=db("SELECT max(sort) as msort FROM $table WHERE del=0 AND place=$place AND sort < $sort");
      if ($sort2) $id2=db("SELECT id FROM $table WHERE del=0 AND place=$place AND sort = $sort2");
    }
    if (isset($_POST['down'])) {
      $sort=db("SELECT sort FROM $table WHERE id=$id");
      $sort2=db("SELECT min(sort) as msort FROM $table WHERE del=0 AND place=$place AND sort > $sort");
      if ($sort2) $id2=db("SELECT id FROM $table WHERE del=0 AND place=$place AND sort = $sort2");
    }
    if ($sort2) {
     $q1="UPDATE $table SET sort=$sort2 WHERE id=$id";
      $q2="UPDATE $table SET sort=$sort WHERE id=$id2";
      mysql_query($q1) or trigger_error(mysql_error());
      mysql_query($q2) or trigger_error(mysql_error());
    }
    header("Location: http://".$_SERVER['HTTP_HOST'].$_SERVER['PHP_SELF']."?place=$place"); 
    exit; 
  }

在数据库中上下移动行

1 个答案: