如何使用美丽的汤和重新找到包含特定文本的特定类的跨度?

时间:2013-04-27 05:33:42

标签: python regex beautifulsoup

如何找到包含以下格式的文本的'blue'类的所有范围:

04/18/13 7:29pm

因此可能是:

04/18/13 7:29pm

或:

Posted on 04/18/13 7:29pm

在构建逻辑方面,这是迄今为止我所得到的:

new_content = original_content.find_all('span', {'class' : 'blue'}) # using beautiful soup's find_all
pattern = re.compile('<span class=\"blue\">[data in the format 04/18/13 7:29pm]</span>') # using re
for _ in new_content:
    result = re.findall(pattern, _)
    print result

我一直指的是https://stackoverflow.com/a/7732827https://stackoverflow.com/a/12229134试图找到一种方法来做到这一点,但以上就是我到目前为止所做的一切。

修改

为了澄清这种情况,有以下内容:

<span class="blue">here is a lot of text that i don't need</span>

<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>

并注意我只需要04/18/13 7:29pm而不是其他内容。

编辑2:

我也尝试过:

pattern = re.compile('<span class="blue">.*?(\d\d/\d\d/\d\d \d\d?:\d\d\w\w)</span>')
for _ in new_content:
    result = re.findall(pattern, _)
    print result

并收到错误:

'TypeError: expected string or buffer'

3 个答案:

答案 0 :(得分:15)

import re
from bs4 import BeautifulSoup

html_doc = """
<html>
<body>
<span class="blue">here is a lot of text that i don't need</span>
<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>
<span class="blue">04/19/13 7:30pm</span>
<span class="blue">Posted on 04/20/13 10:31pm</span>
</body>
</html>
"""

# parse the html
soup = BeautifulSoup(html_doc)

# find a list of all span elements
spans = soup.find_all('span', {'class' : 'blue'})

# create a list of lines corresponding to element texts
lines = [span.get_text() for span in spans]

# collect the dates from the list of lines using regex matching groups
found_dates = []
for line in lines:
    m = re.search(r'(\d{2}/\d{2}/\d{2} \d+:\d+[a|p]m)', line)
    if m:
        found_dates.append(m.group(1))

# print the dates we collected
for date in found_dates:
    print(date)

输出:

04/18/13 7:29pm
04/19/13 7:30pm
04/20/13 10:31pm

答案 1 :(得分:3)

这是一个灵活的正则表达式,您可以使用:

"(\d\d?/\d\d?/\d\d\d?\d?\s*\d\d?:\d\d[a|p|A|P][m|M])"

示例:

>>> import re
>>> from bs4 import BeautifulSoup
>>> html = """
<html>
<body>
<span class="blue">here is a lot of text that i don't need</span>
<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>
<span class="blue">04/19/13 7:30pm</span>
<span class="blue">04/18/13 7:29pm</span>
<span class="blue">Posted on 15/18/2013 10:00AM</span>
<span class="blue">Posted on 04/20/13 10:31pm</span>
<span class="blue">Posted on 4/1/2013 17:09aM</span>
</body>
</html>
"""
>>> soup = BeautifulSoup(html)
>>> lines = [i.get_text() for i in soup.find_all('span', {'class' : 'blue'})]
>>> ok = [m.group(1)
      for line in lines
        for m in (re.search(r'(\d\d?/\d\d?/\d\d\d?\d?\s*\d\d?:\d\d[a|p|A|P][m|M])', line),)
          if m]
>>> ok
[u'04/18/13 7:29pm', u'04/19/13 7:30pm', u'04/18/13 7:29pm', u'15/18/2013 10:00AM', u'04/20/13 10:31pm', u'4/1/2013 17:09aM']
>>> for i in ok:
    print i

04/18/13 7:29pm
04/19/13 7:30pm
04/18/13 7:29pm
15/18/2013 10:00AM
04/20/13 10:31pm
4/1/2013 17:09aM

答案 2 :(得分:2)

这种模式似乎满足了您的需求:

>>> pattern = re.compile('<span class="blue">.*?(\d\d/\d\d/\d\d \d\d?:\d\d\w\w)</span>')
>>> pattern.match('<span class="blue">here is a lot of text that i dont need</span>')
>>> pattern.match('<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>').groups()
('04/18/13 7:29pm',)