Question

使用Python 2.6，当我运行远远低于脚本时会发生以下错误：

Traceback (most recent call last):
  File "g.py", line 7, in <module>
    results  = Geocoder.geocode(row[0])
  File "/usr/lib/python2.6/site-packages/pygeocoder.py", line 261, in geocode
    return GeocoderResult(Geocoder.getdata(params=params))
  File "/usr/lib/python2.6/site-packages/pygeocoder.py", line 223, in getdata
    raise GeocoderError(j['status'], url)
pygeocoder.GeocoderError: Error ZERO_RESULTS
Query: http://maps.google.com/maps/api/geocode/json?region=&sensor=false&bounds=&language=&address=%22++A+FAKE+ADDRESS

Python 2.6脚本：

import csv, string
from pygeocoder import Geocoder

with open('file.csv') as goingGeo:
        theSpreadsheet = csv.reader(goingGeo, quotechar=None)
        for row in theSpreadsheet:
                results  = Geocoder.geocode(row[0])
                (lat, long) = results[0].coordinates
                with open('geo_file.csv', 'a') as f:
                        f.write(row[0] + ",")
                        f.write(row[1] + ",")
                        f.write(row[2] + ",")
                        f.write(row[3] + ",")
                        f.write(row[4] + ",")
                        f.write(row[5] + ",")
                        f.write(row[6] + ",")
                        f.write(row[7] + ",")
                        try:
                                f.write(str(lat))
                        except GeocoderError:            
                                pass
                        f.write(",")
                        try:
                                f.write(str(long))
                        except GeocoderError:            
                                pass
                        f.write('\n')

我只是希望脚本能够继续处理错误。

谢谢！

Answer 1

你有一个write调用周围的try / except块，这些块不可能抛出GeoCoderError，但是你没有尝试/除了调用geocoder()之外可以（显然）确实抛出那个错误。你可能想要这样的东西：

try:
    results  = Geocoder.geocode(row[0])
    (lat, long) = results[0].coordinates
except GeocoderError:
    (lat, long) = (0.0, 0.0)

Answer 2

使用try-except-finally语句，如下所示：

try:
    f.write(str(lat))
except GeocodeError:
    pass
finally:
    do_something_else_regardless_of_above

Answer 3

您使用try: except GeocoderError部分走在正确的轨道上，但它们位于错误的位置。你需要移动它们来包装Geocoder.geocode调用，因为这就是抛出错误：

        for row in theSpreadsheet:
                try:
                        results  = Geocoder.geocode(row[0])
                except GeocoderError:
                        continue
                (lat, long) = results[0].coordinates

另请注意，您需要import来自GeocoderError的{{1}}名称。此外，pygeocoder是Python中的关键字，因此我建议为该变量选择一个不同的名称。

Answer 4

#starting from line 6:
for row in theSpreadsheet:
        try:
            results  = Geocoder.geocode(row[0])
        except:
            pass
#rest of script . . .

您也可以使用“except”来处理特定错误离。

try:
    results=Geocoder.geocode(row[0])
except GeocodeError:
    #deal with error

防止错误停止Python脚本

4 个答案: