我希望我在这里做些傻事......
我正在尝试为Map<String, Phone>
设置JPA注释并获得以下堆栈跟踪。
Exception [EclipseLink-6069] (Eclipse Persistence Services - 2.4.1.v20121003-ad44345): org.eclipse.persistence.exceptions.QueryException
Exception Description: The field [EMPLOYEE.PHONE_TYPE] in this expression has an invalid table in this context.
Query: ReadAllQuery(name="phones" referenceClass=Phone )
at org.eclipse.persistence.exceptions.QueryException.invalidTableForFieldInExpression(QueryException.java:739)
at org.eclipse.persistence.internal.expressions.FieldExpression.validateNode(FieldExpression.java:281)
at org.eclipse.persistence.expressions.Expression.normalize(Expression.java:3259)
at org.eclipse.persistence.internal.expressions.DataExpression.normalize(DataExpression.java:369)
at org.eclipse.persistence.internal.expressions.FieldExpression.normalize(FieldExpression.java:208)
at org.eclipse.persistence.internal.expressions.SQLSelectStatement.normalize(SQLSelectStatement.java:1377)
at org.eclipse.persistence.internal.queries.ExpressionQueryMechanism.buildNormalSelectStatement(ExpressionQueryMechanism.java:546)
at org.eclipse.persistence.internal.queries.ExpressionQueryMechanism.prepareSelectAllRows(ExpressionQueryMechanism.java:1700)
at org.eclipse.persistence.queries.ReadAllQuery.prepareSelectAllRows(ReadAllQuery.java:721)
at org.eclipse.persistence.queries.ReadAllQuery.prepare(ReadAllQuery.java:657)
at org.eclipse.persistence.queries.DatabaseQuery.checkPrepare(DatabaseQuery.java:614)
at org.eclipse.persistence.queries.ObjectLevelReadQuery.checkPrepare(ObjectLevelReadQuery.java:883)
at org.eclipse.persistence.queries.DatabaseQuery.checkPrepare(DatabaseQuery.java:575)
at org.eclipse.persistence.queries.DatabaseQuery.execute(DatabaseQuery.java:820)
at org.eclipse.persistence.queries.ObjectLevelReadQuery.execute(ObjectLevelReadQuery.java:1109)
at org.eclipse.persistence.queries.ReadAllQuery.execute(ReadAllQuery.java:393)
at org.eclipse.persistence.queries.ObjectLevelReadQuery.executeInUnitOfWork(ObjectLevelReadQuery.java:1197)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.internalExecuteQuery(UnitOfWorkImpl.java:2875)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1602)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1584)
at org.eclipse.persistence.internal.indirection.QueryBasedValueHolder.instantiate(QueryBasedValueHolder.java:112)
at org.eclipse.persistence.internal.indirection.QueryBasedValueHolder.instantiate(QueryBasedValueHolder.java:99)
at org.eclipse.persistence.internal.indirection.DatabaseValueHolder.getValue(DatabaseValueHolder.java:88)
at org.eclipse.persistence.internal.indirection.UnitOfWorkValueHolder.instantiateImpl(UnitOfWorkValueHolder.java:161)
at org.eclipse.persistence.internal.indirection.UnitOfWorkValueHolder.instantiate(UnitOfWorkValueHolder.java:222)
at org.eclipse.persistence.internal.indirection.DatabaseValueHolder.getValue(DatabaseValueHolder.java:88)
at org.eclipse.persistence.indirection.IndirectMap.buildDelegate(IndirectMap.java:110)
at org.eclipse.persistence.indirection.IndirectMap.getDelegate(IndirectMap.java:330)
at org.eclipse.persistence.indirection.IndirectMap.size(IndirectMap.java:637)
at org.eclipse.persistence.internal.queries.MapContainerPolicy.sizeFor(MapContainerPolicy.java:830)
at org.eclipse.persistence.internal.indirection.TransparentIndirectionPolicy.instantiateObject(TransparentIndirectionPolicy.java:386)
at org.eclipse.persistence.mappings.ForeignReferenceMapping.buildCloneFromRow(ForeignReferenceMapping.java:285)
at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildAttributesIntoWorkingCopyClone(ObjectBuilder.java:1594)
at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildWorkingCopyCloneFromRow(ObjectBuilder.java:1741)
at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildObjectInUnitOfWork(ObjectBuilder.java:668)
at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildObject(ObjectBuilder.java:605)
at org.eclipse.persistence.internal.descriptors.ObjectBuilder.buildObject(ObjectBuilder.java:564)
at org.eclipse.persistence.queries.ObjectLevelReadQuery.buildObject(ObjectLevelReadQuery.java:777)
at org.eclipse.persistence.queries.ReadAllQuery.registerResultInUnitOfWork(ReadAllQuery.java:783)
at org.eclipse.persistence.queries.ReadAllQuery.executeObjectLevelReadQuery(ReadAllQuery.java:434)
at org.eclipse.persistence.queries.ObjectLevelReadQuery.executeDatabaseQuery(ObjectLevelReadQuery.java:1150)
at org.eclipse.persistence.queries.DatabaseQuery.execute(DatabaseQuery.java:852)
at org.eclipse.persistence.queries.ObjectLevelReadQuery.execute(ObjectLevelReadQuery.java:1109)
at org.eclipse.persistence.queries.ReadAllQuery.execute(ReadAllQuery.java:393)
at org.eclipse.persistence.queries.ObjectLevelReadQuery.executeInUnitOfWork(ObjectLevelReadQuery.java:1197)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.internalExecuteQuery(UnitOfWorkImpl.java:2875)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1602)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1584)
at org.eclipse.persistence.internal.sessions.AbstractSession.executeQuery(AbstractSession.java:1549)
at org.eclipse.persistence.internal.jpa.QueryImpl.executeReadQuery(QueryImpl.java:231)
at org.eclipse.persistence.internal.jpa.QueryImpl.getResultList(QueryImpl.java:411)
at aaa.Test.main(Test.java:20)
创建的表格如下:
EMP_PHONE
=================================
EMP_ID PHONES_ID PHONE_TYPE
------ --------- ----------
42 1 NULL
EMPLOYEE
=================================
ID
--
42
PHONE
=================================
ID NUM
-- --------
1 867-5309
NULL
PHONE_TYPE
似乎告诉我一些时髦的事情,以及eclipselink寻找EMPLOYEE.PHONE_TYPE
的方式让我觉得它正在考虑来自{{1}的关系} - &gt; PHONE
而不是相反。
JPA实体定义如下。电话映射是单向的,Phone对象应由多个Employees共享(不是我的实际类型,但这个简化的示例演示了这个问题)
EMPLOYEE
使用以下测试代码
@Entity
public class Employee {
@Id private long id;
@OneToMany(cascade=CascadeType.ALL)
@JoinTable(name="EMP_PHONE", joinColumns=@JoinColumn(name="EMP_ID"))
@MapKeyColumn(name="PHONE_TYPE")
private Map<String, Phone> phones = new HashMap<String, Phone>();
public Employee() {}
public Employee(long id) {
this.id = id;
}
public long getId() {
return id;
}
public Map<String, Phone> getPhones() {
return phones;
}
}
@Entity
public class Phone {
@Id
private long id;
private String num;
public String getNum() {
return num;
}
public Phone() {}
public Phone(String num) {
this.num = num;
}
public Phone(long id, String num) {
this.id = id;
this.num = num;
}
public long getId() {
return id;
}
}
和persistence.xml:
EntityManagerFactory factory = Persistence.createEntityManagerFactory("test");
EntityManager em = factory.createEntityManager();
Employee employee = new Employee(42);
// exception will occur with or without phones added to the map
employee.getPhones().put("home", new Phone(1, "867-5309"));
em.getTransaction().begin();
em.persist(employee);
em.getTransaction().commit();
Query q = em.createQuery("select o from Employee o");
q.setHint("javax.persistence.cache.storeMode", "REFRESH");
q.getResultList(); // EXCEPTION THROWN HERE
我在Windows 7上运行,使用Oracle XE 11g作为数据库。提前感谢任何见解!
答案 0 :(得分:11)
这看起来像EclipseLink错误364922:
具有单向OneToMany属性和@MapKeyColumn批注的实体创建了正确的数据库表,映射表包含“键列,但持久化实体仅填充id列而不是键列。持久化操作不会抛出错误,但后续查询很快就会失败并出现以下错误: 异常说明:此表达式中的[ORGANIZATION.MAILINGADDRESSES_KEY]字段在此上下文中具有无效表。
为了它的价值,我使用Hibernate / H2测试了你的代码,它工作正常。
<强>更新强>
我刚用EclipseLink测试了这个。如果您为MapKeyColumn
显式设置了表,则会正确填充密钥。即:
@MapKeyColumn(name="PHONE_TYPE", table="EMP_PHONE")