创建一个find方法

Question

我正在尝试从头开始创建一个find方法，看看两个对象是否相等，只要某些成员相等，使用Equals方法这样做。我知道使用Find / Contains方法会更快，但我不能使用它们。方法的签名是“static int Find（List c，Coffee x）”find c in c并返回有效索引（例如0,1），如果x存在于c中，则返回-1。必须使用equals方法来确定等效性。如果传递的对象不等于列表中的当前对象，则将其添加到列表中（该列表包含从基类派生的两种类型的对象，因此列表可以存储这两种类型）。等值是由名称，成本，需求，持有成本和烘焙类型定义的常规和名称，成本，需求，持有成本和无咖啡因的最小数量。这是我到目前为止所做的：

  static void Main(string[] args)
    {

        // Create objects and references
        Coffee obv = new Coffee();
        Decaf decafCoffee = null;
        Regular regularCoffee = null;
        List<Coffee> inventory = new List<Coffee>();


        // Prompt user for input and store it as a string
        Console.Write("Enter q to quit or the whole data as a comma delimited string using the following format Name,D,C,D:minQ or R:roast ");
        string s = Console.ReadLine();

        // Loop
        while (!s.ToLower().Equals("q"))
        {
            // Split string up and assign componets to variables
            string[] values = s.Split(",".ToCharArray(), StringSplitOptions.RemoveEmptyEntries);
            string name = values[0];
            string demand = (values[1]);
            string cost = (values[2]);
            string type = values[3];

            // Check for > 0 and convert to numbers
            float D = CheckDemand(demand);
            float C = CheckCost(cost);
            float M = 0;

            if (type.StartsWith("D:"))
            {
                type = Regex.Match(type, @"\d+").Value;
                M = CheckMin(type);
                decafCoffee = new Decaf(name, D, C, M);
                inventory.Add(decafCoffee);
            }

            else if (type.StartsWith("R:"))
            {
                if (type.Contains("light"))
                {
                    M = 1;
                    regularCoffee = new Regular(name, D, C, M);
                    inventory.Add(regularCoffee);
                }
                else if (type.Contains("medium"))
                {
                    M = 2;
                    regularCoffee = new Regular(name, D, C, M);
                    inventory.Add(regularCoffee);
                }

                else if (type.Contains("dark"))
                {
                    M = 3;
                    regularCoffee = new Regular(name, D, C, M);
                    inventory.Add(regularCoffee);
                }
                else Console.WriteLine("\nError, please enter all lower case \"dark\", \"medium\", or \"light\" next time.");
            }

            else Console.WriteLine("\nError, please enter either \"D:\" followed by a number or \"R:\" followed by roast type next time.");
            Console.Write("\nEnter q to quit or the whole data as a comma delimited string using the following format Name,D,C,D:minQ or R:roast: ");
            s = Console.ReadLine();
        }   // End loop

        // Sort and  display values
        var sortedList = inventory.OrderBy(i => i.Q()).ToList();
        Console.WriteLine("\nName \t   C ($)      Demand \t  Detail   Q(lbs.)     TAC
        for (int j = 0; j < inventory.Count; j++)
        {
            Console.WriteLine("{0}", sortedList[j].toString());
        }

        Console.WriteLine(obv.toStringQ());

这就是我对equals方法所拥有的：

public override bool Equals(object obj)
    {
        if (obj is Coffee)
        {
            bool isNameEqual = Name.Equals(this.Name);
            bool isuCostEqual = Cost.Equals(this.Cost);
            bool isDemandEqual = Demand.Equals(this.Demand);
            bool ishCostEqual = h.Equals(this.h);
            bool isMinEqual = getQ.Equals(this.getQ);

            return (isNameEqual && isuCostEqual && isDemandEqual && ishCostEqual && isMinEqual);
        }
        return false;
    }

如何使用find方法？

Answer 1

在Coffee上实现'Equals'方法，并可选择在其子类上实现，例如Decaf，Regular等。现在，您可以直接在列表中使用Contains方法。