因为我非常喜欢编程,我喜欢在空闲时间编程,所以我试图创建一个输出看起来像x的代码。像这样的东西。
x x
x x
x
x x
x x
所以我希望用户输入“x”的高度。这是我到目前为止的代码,我真的不知道如何继续前进。我只需要一个提示或者是否有人可以告诉我哪里出错了。
import java.util.Scanner;
public class x{
public static void main(String[] args){
Scanner kbd = new Scanner(System.in);
int height;
System.out.print("Enter the height of the X: " );
height = kbd.nextInt();
for (int i = 1; i <= height; i++){
for (int j = 1; j <= height; j++) {
if(i ==j || j+i == height + 1)
System.out.println("x");
else
System.out.print(" ");
}
}
}
}
答案 0 :(得分:5)
两个变化:
将System.out.println("x");
更改为System.out.print("x");
(打印后删除ln)
后两行
System.out.print(" ");
}
添加
System.out.println();
答案 1 :(得分:0)
for (int i = 0; i < height; i++){
for (int j = 0; j < height; j++) {
if(i == j || j + i == height - 1)
System.out.print("x");
else
System.out.print(" ");
}
System.out.println();
}
答案 2 :(得分:0)
对于X的奇数和偶数高度,这适用于我:
import java.util.Scanner;
public class x{
public static void main(String[] args){
Scanner kbd = new Scanner(System.in);
int height;
System.out.print("Enter the height of the X: " );
height = kbd.nextInt();
for (int i = 0; i <= height; i++){
for (int j = 0; j <= height; j++) {
if( (i ==j && i!=0 ) || j+i == height + 1) //needed to check for i or j !=0
System.out.print("x"); //this shouldn't be println
else
System.out.print(" ");
}
System.out.println(); //you needed this
}
}
}