新手到Python ....通过以下任务请求帮助: - )
我有各种文件的树,其中一些是C源代码。 我想用python脚本修改这些C文件。
C代码有4个定义 -
#define ZR_LOG0(Id, Class, Seveity, Format)
#define ZR_LOG1(Id, Class, Seveity, Format, Attr0)
#define ZR_LOG2(Id, Class, Seveity, Format, Attr0, Attr1)
#define ZR_LOG3(Id, Class, Seveity, Format, Attr0, Attr1, Attr2)
在C源代码中有各种ZR_LOGn行。
示例:ZR_LOG1(1,LOG_CLASS_3,LOG_INFO,“hello world%d”,76);
空格(空格,制表符)可能出现在该行的任何位置(字段之间)。
python脚本任务如下:
在单独的输出文件中,对于每个ZR_LOG行,我们将以格式创建索引行 {NewId,Format}, 以上示例将获得:
{ 0, "hello world %d" },
感谢你的帮助......
我已经开始使用以下代码,您可以查看它或完全忽略它。
'''
Created on Oct 25, 2009
@author: Uri Shkolnik
The following version does find & replace LOG Ids for all
C source files in a dir (and below) with sequential counter,
The files are assumed to be UTF-8 encoded.
(which works fine if they are ASCII, because ASCII is a
subset of UTF-8)
It also assemble new index file, composed from all new IDs and format fields
'''
import os, sys, re, shutil
mydir= '/home/uri/proj1'
searched_pattern0 = 'ZR_LOG0'
def search_and_replace(filepath):
''' replaces all string by a regex substitution '''
backupName=filepath+'~re~'
print 'reading:', filepath
input = open(filepath,'rb')
s=unicode(input.read(),'utf-8')
input.close()
m = re.match(ur'''[:space:]ZR_LOG[0-3].*\(.*[0-9]{0,10},LOG_''', s)
print m
def c_files_search(dummy, dirr, filess):
''' search directories for file pattern *.c '''
for child in filess:
if '.c' == os.path.splitext(child)[1] and os.path.isfile(dirr+'/'+child):
filepath = dirr+'/'+child
search_and_replace(filepath)
os.path.walk(mydir, c_files_search, 3)
答案 0 :(得分:1)
几点:
所以,我会做这样的事情:
output = ''
counter = 1
for line in lines:
# Match only ZR_LOG lines and capture everything surrounding "Id"
match = re.match('^(.*\sZR_LOG[0-3]\s*\(\s*)' # group(1), before Id
'Id'
'(,.*)$', # group(2), after Id
line)
if match:
# Add everything before Id, the counter value and everything after Id
output += match.group(1) + str(counter) + match.group(2)
counter += 1
# And do extra logging etc.
else:
output += line