我正在使用Twitter API和python,当我尝试合并我检索的JSON页面时,我遇到了问题。
为每个请求检索的JSON结构为:
{
"previous_cursor": 0,
"previous_cursor_str": "0",
"next_cursor": 1333504313713126852,
"users": [
{
"foo": "bar",
"foo": "bar",
"foo": "bar",
"foo": "bar",
"foo": "bar"
},
{
"foo": "bar",
"foo": "bar",
"foo": "bar",
"foo": "bar",
"foo": "bar"
},
{
"foo": "bar",
"foo": "bar",
"foo": "bar",
"foo": "bar",
"foo": "bar"
}
],
"next_cursor_str": "1333504313713126852"
}
我需要合并每个用户信息的一个列表中的所有数据。问题在于,当我这样做时,我得到了这个结构:
friends_list = [friends_list, raw_friends_list['users']]
[
{"foo": "bar","foo": "bar"}
{"foo": "bar","foo": "bar"}
{"foo": "bar","foo": "bar"}
]
[
{"foo": "bar","foo": "bar"}
{"foo": "bar","foo": "bar"}
{"foo": "bar","foo": "bar"}
]
而不是:
[
{"foo": "bar","foo": "bar"}
{"foo": "bar","foo": "bar"}
{"foo": "bar","foo": "bar"}
{"foo": "bar","foo": "bar"}
{"foo": "bar","foo": "bar"}
{"foo": "bar","foo": "bar"}
]
有没有人知道用python实现这个目的的正确方法?
此致
答案 0 :(得分:0)
friends_list.extend(raw_friends_list['users'])