我想继续执行for循环，直到函数里面返回值，但是我的代码中的问题首先是当我在调试器中检查时，for循环从5直接开始而不是0，其次是在它返回之前第二个请求发送的第一个值。我不想使用超时功能
我正在使用Jquery 1.9.1和web-SQL。
function MakeSyncCall(rdosync) {
$('#hdrProgress').show();
$('#contentProgress').show();
var db = CreateDB();
var query = '';
var row = '';
query = "Select * From " + tablename + " order by ord_key";
db.transaction(populateDB, errorDB, successDB);
function populateDB(tx) {
tx.executeSql(query, [], function (tx, results) {
var result = [];
var len = results.rows.length;
debugger;
if (len > 0) {
for (var iv = 0; iv < len; iv++) {
var row = results.rows.item(iv);
rdosync = row['ord_key'];
var ReturnedValue= ForLoop(rdosync);
} //FOR LOOP
} ///Main if
else {
alert('No Records to Sync');
$('#hdrProgress').hide();
$('#contentProgress').hide();
}
});
}
function errorDB(err) {
alert("Error processing MakeSyncCall: " + err.message);
}
function successDB() {
}
}
function ForLoop(rdosync) {
alert(rdosync);
var tablename = 'SyncCheck';
var arrcolumnName = ['ord_key', 'SpecialInstruction', 'Interview', 'RoofModule', 'FireProtection'];
CreateTableWithDB(tablename, arrcolumnName);
query = "Select * From " + tablename + " where SpecialInstruction ='Y' and Interview= 'Y' and RoofModule ='Y' and FireProtection= 'Y' and ord_key = ?";
db.transaction(populateDB, errorDB, successDB);
function populateDB(tx) {
tx.executeSql(query, [rdosync], function (tx, results) {
var result = [];
var len = results.rows.length;
debugger;
if (len > 0) {
return row['ord_key']
}
else {
alert(rdosync + " cannot be sync.Please complete all sections");
$('#hdrProgress').hide();
$('#contentProgress').hide();
}
});
}
function errorDB(err) {
alert("Error processing MakeSyncCall: " + err.message);
$('#hdrProgress').hide();
$('#contentProgress').hide();
}
function successDB() {
}
}
在此我想用其参数执行forloop函数并等待其返回值，然后继续第二个请求。