我正在编写一个程序来替换另一个进程内存中的字符串。它需要用C语言编写,因为我的目标平台不支持任何更高级别的语言。
最初,我不是直接跳转到内存修改,而只是尝试将内存读入缓冲区,以便我可以识别字节字符串所在的偏移量,这样我就可以开始修改它了。
我已经阅读了每个堆栈溢出问题和我可以找到的代码示例,以及手册页和一些一般的试错。我的C有点生疏,所以这证明是相当具有挑战性的。我读过的例子似乎采取了两种不同的方法:
或
这是我的代码。
计划附加到:
#include <stdio.h>
int main(int argc, char *argv[]){
printf("Spinning up....\n");
char changeme[6] = "AAAAA";
printf("ready for change....\n");
getchar();
printf("changeme is %s\n", changeme);
return 0;
}
转储内存的程序:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/ptrace.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <sys/user.h>
#include <sys/syscall.h>
#include <unistd.h>
#include <limits.h>
#include <stdint.h>
#include <fcntl.h>
#include <wait.h>
#include <errno.h>
int main(int argc, char *argv[]){
char mempath[PATH_MAX];
uintptr_t const address = strtoul(argv[2], NULL, 0);
int waitval = 0;
pid_t target_process = atoi(argv[1]);
struct user_regs_struct regs;
int readbytes = 0;
if (ptrace(PTRACE_ATTACH,target_process,NULL,NULL))
perror("attach");
printf("attatched!\n");
waitpid(target_process, NULL, 0);
sprintf(mempath, "/proc/%s/mem", argv[1]);
printf("ready! opening %s\n", mempath);
int memfd = open(mempath, O_RDONLY);
printf("memfd = %d\n", memfd);
char *outbuf = malloc(_SC_PAGE_SIZE);
printf("trying to read %d bytes from offset %lu\n",_SC_PAGE_SIZE,address);
if (outbuf){
lseek(memfd, address, SEEK_SET);
readbytes = read(memfd, outbuf, _SC_PAGE_SIZE);
if (_SC_PAGE_SIZE == readbytes)
printf("read success! - %s\n", outbuf);
else
printf("readfailed! read %d bytes: %s\n", readbytes, outbuf);
printf("oh noes! %s\n", strerror(errno));
free(outbuf);
}
return 0;
}
终端输出:
终端1:
[10:59] tel0s@Relentless:~/research$ ./changeme
Spinning up....
ready for change....
终端2:
[11:35] tel0s@Relentless:~/research$ ps aux | grep changeme
tel0s 7763 0.0 0.0 4076 352 pts/2 S+ 10:59 0:00 ./changeme
tel0s 8297 0.0 0.0 8948 928 pts/1 S+ 11:35 0:00 grep --colour=auto changeme
[11:35] tel0s@Relentless:~/research$ cat /proc/7763/maps
00400000-00401000 r-xp 00000000 fd:00 2260791 /home/tel0s/research/changeme
00600000-00601000 r--p 00000000 fd:00 2260791 /home/tel0s/research/changeme
00601000-00602000 rw-p 00001000 fd:00 2260791 /home/tel0s/research/changeme
7fb2cfc56000-7fb2cfdf7000 r-xp 00000000 fd:00 4890420 /lib64/libc-2.17.so
7fb2cfdf7000-7fb2cfff6000 ---p 001a1000 fd:00 4890420 /lib64/libc-2.17.so
7fb2cfff6000-7fb2cfffa000 r--p 001a0000 fd:00 4890420 /lib64/libc-2.17.so
7fb2cfffa000-7fb2cfffc000 rw-p 001a4000 fd:00 4890420 /lib64/libc-2.17.so
7fb2cfffc000-7fb2d0000000 rw-p 00000000 00:00 0
7fb2d0000000-7fb2d0022000 r-xp 00000000 fd:00 4888842 /lib64/ld-2.17.so
7fb2d01f2000-7fb2d01f5000 rw-p 00000000 00:00 0
7fb2d021e000-7fb2d0221000 rw-p 00000000 00:00 0
7fb2d0221000-7fb2d0222000 r--p 00021000 fd:00 4888842 /lib64/ld-2.17.so
7fb2d0222000-7fb2d0223000 rw-p 00022000 fd:00 4888842 /lib64/ld-2.17.so
7fb2d0223000-7fb2d0224000 rw-p 00000000 00:00 0
7fff03290000-7fff032b1000 rw-p 00000000 00:00 0 [stack]
7fff03394000-7fff03395000 r-xp 00000000 00:00 0 [vdso]
ffffffffff600000-ffffffffff601000 r-xp 00000000 00:00 0 [vsyscall]
[11:36] tel0s@Relentless:~/research$ sudo ./writeprocmem 7763 400000
attatched!
ready! opening /proc/7763/mem
memfd = 3
trying to read 30 bytes from offset 400000
readfailed! read -1 bytes:
oh noes! Input/output error
我可能的原因是:
任何帮助都会非常好,而且我更愿意回答我所犯的错误,而不仅仅是让我直接使用代码,因为我想从根本上理解这一点,而不仅仅是让我的代码正常运行。
答案 0 :(得分:2)
您应该检查系统调用的返回状态。如果它们失败,将设置errno以指示出错的地方,并且您可以使用perror()显示相关文本。
E.g。类似的东西:
if (lseek(memfd, address, SEEK_SET) < 0) {
perror("lseek");
}
readbytes = read(memfd, outbuf, _SC_PAGE_SIZE);
if (readbytes < 0) {
perror("read");
}
Roy Hills
答案 1 :(得分:0)
uintptr_t const address = strtoul(argv[2], NULL, 0);
[11:36] tel0s @ Relentless:〜/ research $ sudo ./writeprocmem 7763 400000
printf("trying to read %d bytes from offset %lu\n",_SC_PAGE_SIZE,address);
你告诉strtoul基数是零,来自/ proc // maps的地址是十六进制,你调试用十进制打印出来。不幸的是,你的地址恰好是一个十六进制和十进制有效的数字。
要么在命令行上使用0x400000,要么告诉strtoul使用base 0x10
您还想使用sysconf(_SC_PAGESIZE)或getpagesize()。