我目前正在尝试检索JS返回值,但我真的不知道为什么它不能正常工作......
嗨,我的代码是最容易阅读的,请提前感谢:
<script type="text/javascript">
function getValLocalSto(key, URL){
console.log(key);
console.log(URL);
var myKey = localStorage.getItem(key);
if(myKey == null){
// getting back JSON data
$.ajax({
url: URL,
dataType: 'json',
async: false,
success: function (json) {
var test;
console.log(JSON.stringify(json)); // the result is a well formed JSON string
localStorage.setItem(key,JSON.stringify(json));
myKey = localStorage.getItem(key);
test =jQuery.parseJSON(myKey);
console.log("My function result : "+test); // the result is a [object Object]
return test;
}
});
}else {
// Other work whatever
}
}
//call my function
console.log("sortie fonction : "+getValLocalSto("testJson", "do/profil")); // the result is "undefined"
var myuResult = getValLocalSto("testJson", "do/profil")); // the result is "undefined"
console.log(ff.prenom);
document.getElementById("myDiv").innerHTML="<div><input disabled='disabled' name='text-basic' id='text-basic' type= 'text' value='Votre nom "+ff.nom+"'/></div>";
document.getElementById("myDiv").innerHTML+="<div> <input disabled='disabled' name='text-basic' id='text-basic' type= 'text' value= 'Votre prenom "+ff.prenom+"'/></div>";
</script>
解决方案:
function getValLocalSto(key, URL){
// do my stuff
});
}else {
// Other work whatever
}
return test;
}
答案 0 :(得分:0)
您可以将回调传递给AJAX。 将功能定义更改为:
function getValLocalSto(key, URL, callback){
...
$.ajax({
url: URL,
dataType: 'json',
async: false,
success: callback
});
...
代码中的:
getValLocalSto("testJson", "do/profil", function(data) {
localStorage.setItem(key,JSON.stringify(data));
myKey = localStorage.getItem(key);
test = jQuery.parseJSON(myKey);
// here you work with test as you want as a result of getValLocalSto
});
答案 1 :(得分:0)
只需在getValLocalSto外部函数中使用变量作用域声明测试变量在ajax成功函数之外。否则,您需要一个回调来从ajax成功函数返回变量。试试这个:
<script type="text/javascript">
function getValLocalSto(key, URL){
...
if(myKey == null){
// getting back JSON data
var test;
$.ajax({
url: URL,
dataType: 'json',
async: false,
success: function (json) {
console.log(JSON.stringify(json)); // the result is a well formed JSON string
localStorage.setItem(key,JSON.stringify(json));
myKey = localStorage.getItem(key);
test =jQuery.parseJSON(myKey);
console.log("My function result : "+test); // the result is a [object Object]
}
});
return test;
}else {
// Other work whatever
}
}
//call my function
console.log("sortie fonction : "+getValLocalSto("testJson", "do/profil")); // the result is "undefined"
...
</script>