目前,我正在尝试在Android应用程序中开发录音机,最终发送到在线服务器,然后进行多播。但是在我继续之前,我遇到了像Unhandled exception type IOException这样的错误。我在错误出现的部分添加了**符号。请帮忙。
package com.example.testproject;
import java.io.File;
import android.app.Activity;
import android.media.MediaPlayer;
import android.media.MediaRecorder;
import android.os.Bundle;
import android.os.Environment;
import android.view.View;
public class Sound extends Activity {
private MediaPlayer mediaPlayer;
private MediaRecorder recorder;
private String OUTPUT_FILE;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.audio);
OUTPUT_FILE=Environment.getExternalStorageDirectory()+"/audiorecorder.3gpp";
}
public void buttonTapped(View view){
switch(view.getId()){
case R.id.btnstart:
try {
beginRecording();
}catch(Exception e){
e.printStackTrace();
}
break;
case R.id.btnfinish:
try {
stopRecording();
}catch(Exception e){
e.printStackTrace();
}
break;
case R.id.btnplay:
try {
playRecording();
}catch(Exception e){
e.printStackTrace();
}
break;
case R.id.btnstop:
try {
stopPlayback();
}catch(Exception e){
e.printStackTrace();
}
break;
}
}
private void stopPlayback(){
}
private void playRecording() throws Exception{
ditchMediaPlayer();
mediaPlayer = new MediaPlayer();
mediaPlayer.setDataSource(OUTPUT_FILE);
mediaPlayer.prepare();
mediaPlayer.start();
}
private void ditchMediaPlayer(){
if(mediaPlayer != null)
{
try{
mediaPlayer.release();
}catch(Exception e)
{
e.printStackTrace();
}
}
}
private void stopRecording(){
if(recorder != null)
recorder.stop();
}
private void beginRecording(){
ditchMediaRecorder();
File outputFile = new File(OUTPUT_FILE);
if(outputFile.exists())
outputFile.delete();
recorder = new MediaRecorder();
recorder.setAudioSource(MediaRecorder.AudioSource.MIC);
recorder.setOutputFormat(MediaRecorder.OutputFormat.THREE_GPP);
recorder.setAudioEncoder(MediaRecorder.AudioEncoder.AMR_NB);
recorder.setOutputFile(OUTPUT_FILE);
**recorder.prepare();**
recorder.start();
}
private void ditchMediaRecorder() {
if(recorder != null)
recorder.release();
}
}
答案 0 :(得分:1)
您必须处理调用recorder.prepare()时可能发生的IO错误。有关异常处理的更多信息,请参阅the official Java docs。
目前,这应该有所帮助:
try {
recorder.prepare();
recorder.start();
} catch (IOException e) {
e.printStackTrace();
}
但请确保在发布应用程序之前实施正确的错误处理。