Any()接受一个Func 如何动态构建过滤器?即:
var filter = () a=> a.Text == "ok";//add the first filter
if (flag)
filter += () a=> a.ID == 5;//add the second filter << obviously this doesn't work.
list.Any(filter);
我还看到了代码组合表达式&gt; ,但我不能让它工作,因为我不知道如何将其转换为Func
非常感谢任何帮助。
答案 0 :(得分:3)
您可以通过调用当前过滤器中的其他过滤器来组合过滤器,如下所示:
var input = new[] {"quick", "brown", "fox", "jumps"};
Func<string,bool> filter1 = a => a == "quick";
Func<string,bool> filter2 = a => filter1(a) || a.Length == 3;
foreach (var s in input.Where(filter2)) {
Console.WriteLine(s);
}
打印
quick
fox
您可以对LINQ的任何基于谓词的函数使用相同的方法,包括Any
:
if (input.Any(filter2)) {
...
}
答案 1 :(得分:0)
您可以像Any
这样添加多个过滤器。
list.Any(a=>a.Text == "ok" && a.ID == 5);
答案 2 :(得分:0)
您可以创建IEnumerable<Func<T,bool>>
然后查询它,例如
Func<int,bool> isGreaterThanEight = x => x > 8;
Func<int,bool> isEven = x => x % 2 == 0;
Func<int,bool> hasFactorFive = x => x % 5 == 0;
IEnumerable<Func<int,bool>> rules = new List<Func<int,bool>>()
{ isGreaterThanEight, isEven, hasFactorFive };
var nums = Enumerable.Range(1,10);
var actual = nums.Where( x => rules.Any( r => r(x) ) );
Assert.That( actual, Is.EqualTo( new[]{2,4,5,6,8,9,10} ) );