Question

我的UITableViewCell中的uiswitch存在问题，每当我更改属于特定部分的特定单元格中的切换值时。具有相同inexPath.row的所有其他部分单元格都会发生变化。请帮忙？

以下是我的cellForRowAtIndexPath方法代码：

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *CellIdentifier = @"Cell";
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];

    //UISwitch *switchview = nil ;

    if (cell == nil)
    {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault
                                      reuseIdentifier:CellIdentifier];



    }


    UISwitch *switchController = [[UISwitch alloc] initWithFrame:CGRectZero];
    CGRect switchFrame = switchController.frame;
    NSString *str = [[self.SwitchArray objectAtIndex:indexPath.section] objectAtIndex:indexPath.row];
    NSLog(@"string in cell%@", str);


    //set its x and y value, this you will have to determine how to space it on the left side
    switchFrame.origin.x = 50.0f;
    switchFrame.origin.y = 10.0f;
    switchController.frame = switchFrame;


    [switchController addTarget:self action:@selector(switchChanged:) forControlEvents:UIControlEventValueChanged];
    [cell addSubview:switchController ];
    [addSubview:switchController];


    if ([[[self.SwitchArray objectAtIndex:indexPath.section] objectAtIndex:indexPath.row ]isEqualToString:@"ON"])
 {
        switchController.on=YES;
 }
    else
    {
        switchController.on=NO;
    }


    return cell;

}

这是SwitchChangedEvent：

-(void)switchChanged:(UISwitch *)sender
{
    UITableViewCell *cell = (UITableViewCell *)[sender superview];
    NSIndexPath *index=[mainTableView indexPathForCell:cell];

    if (sender.on)
    {

        [[self.SwitchArray objectAtIndex:index.section] replaceObjectAtIndex:index.row withObject:@"ON"];
        NSString *word= [[self.mainArray objectAtIndex:index.section ] objectAtIndex:index.row];

    }
    else
    {
        //call the first array by section
        [[self.SwitchArray objectAtIndex:index.section] replaceObjectAtIndex:index.row withObject:@"OFF"];
        NSString *word= [[self.mainArray objectAtIndex:index.section ] objectAtIndex:index.row];


   }

    [padFactoids setObject:[NSKeyedArchiver archivedDataWithRootObject:SwitchArray] forKey:@"savedArray"];
    [padFactoids synchronize];

}

Answer 1

您有两个主要问题：

此代码错误：
```
  [cell addSubview:switchController ];
```
永远不要在细胞中添加子视图;只将其添加到单元格的contentView。
您每次都会通过cellForRowAtIndexPath:添加切换。但这些细胞正在重复使用。所以一些单元已经拥有开关。因此，您要向某些单元格添加许多开关。

Answer 2

如果你看，我想你会发现你正在构建多个交换机并在每个单元上。

当细胞被重复使用时，您添加一个新的开关但不删除旧的开关。我认为这至少是问题原因的一部分。

<强>更新

我想我会处理这个问题的方式与其他人不同。我认为@AlanoudAldrees将更容易删除旧的交换机。

if (cell == nil)
{
    cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault
                                  reuseIdentifier:CellIdentifier];
}
else
{
    for (UIView *view in cell.subviews)
        if ([view isKindOfClass:[UISwitch class]])
            [view removeFromSuperview];
}

Answer 3

正如其他人已经指出的那样，您要为每个单元格添加多个开关。 FTFY：

UISwitch *switchController = nil;
if (cell == nil)
{
    cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault
                                  reuseIdentifier:CellIdentifier];
    switchController = [[UISwitch alloc] initWithFrame:CGRectZero];
    switchController.tag = 'swch';
    CGRect switchFrame = switchController.frame;
    //set its x and y value, this you will have to determine how to space it on the left side
    switchFrame.origin.x = 50.0f;
    switchFrame.origin.y = 10.0f;
    switchController.frame = switchFrame;
    [switchController addTarget:self action:@selector(switchChanged:) forControlEvents:UIControlEventValueChanged];
    [cell.contentView addSubview:switchController];
}
else 
{
    switchController = (UISwitch*)[cell.contentView viewWithTag: 'swch'];
    NSAssert(switchController != nil, @"how?");
}

NSString *str = [[self.SwitchArray objectAtIndex:indexPath.section] objectAtIndex:indexPath.row];
NSLog(@"string in cell%@", str);

switchController.on = [str isEqualToString:@"ON"];

return cell;

表单元格中的UIswitch重用

3 个答案: