Question

架构：

CREATE TABLE #exclGeoKeys (xKEY INT);
INSERT INTO #exclGeoKeys
    values
    (1),
    (2);

CREATE TABLE #y (NAME CHAR(1),xKEY INT);
INSERT INTO #y
    values
    ('A',1),
    ('C',2),
    ('D',NULL),
    ('E',3),
    ('F',4);

我可以缩短以下内容，以便产生相同的结果，而不需要OR xKEY IS NULL部分吗？

SELECT *
FROM   #y
WHERE  xKEY NOT IN 
                 (
                 SELECT * 
                 FROM #exclGeoKeys
                 ) 
       OR 
       xKEY IS NULL;

Answer 1

使用NOT EXISTS运算符

选项

SELECT *
FROM #y t
WHERE NOT EXISTS (
                  SELECT 1
                  FROM #exclGeoKeys t2
                  WHERE t.xKEY = t2.xKEY
                  )

SQLFiddle上的演示

EXISTS和EXCEPT运算符选项

SELECT *
FROM #y t
WHERE EXISTS (
              SELECT t.xKEY
              EXCEPT
              SELECT t2.xKEY
              FROM #exclGeoKeys t2
              )

使用NOT EXISTS和INTERSECT运算符的选项

SELECT *
FROM #y t
WHERE NOT EXISTS (
                  SELECT t.xKEY
                  INTERSECT
                  SELECT t2.xKEY
                  FROM #exclGeoKeys t2
                  )

Answer 2

试试这些：

--USING NOT EXISTS (DOES NOT REQUIRE THE IS NULL SECTION)

SELECT *
FROM #y AS T1
WHERE NOT EXISTS(SELECT * FROM #exclGeoKeys AS T2 WHERE T1.xKEY = T2.xKEY) 
--OR T1.xKEY IS NULL;

--USING NOT IN
SELECT *
FROM #y AS T1
WHERE T1.xKEY NOT IN (SELECT T2.xKEY FROM #exclGeoKeys AS T2) 
OR T1.xKEY IS NULL;

希望这有帮助

Answer 3

虚幻价值

SELECT *
FROM   #y
WHERE  coalesce(xKEY,-1) NOT IN 
                 (
                 SELECT *
                 FROM #exclGeoKeys
                 )

Answer 4

试图使用左连接？

SELECT #y.*
FROM   #y
LEFT JOIN #exclGeoKeys excl on excl.xKEY = #y.xKEY
WHERE excl.xKEY IS NULL

结合和缩短两个where子句条件

4 个答案: