我需要一个与SQL Server中的Oracle WM_CONCAT
类似的函数,它返回一个逗号分隔的列表,其中包含您作为参数传递的任何字段。例如,在Oracle中,
select WM_CONCAT(first_name) from employee where state='CA'
返回“John,Jim,Bob”。
如何在SQL Server中执行此操作?
由于
答案 0 :(得分:3)
实际答案:
SELECT
SUBSTRING(buzz, 2, 2000000000)
FROM
(
SELECT
firstname
FROM
employee
WHERE
State = 'CA'
FOR XML PATH (',')
) fizz(buzz)
这是一个常见的问题。一些搜索:
答案 1 :(得分:2)
试试这个:
drop table #mike_temp
go
select * into #mike_temp
from (select 'Ken' as firstname, 'CO' as state
union all
select 'Mike' as firstname, 'CO' as state
union all
select 'Tom' as firstname , 'WY' as state
) a
go
SELECT distinct
state
,STUFF((SELECT ', ' + b.firstname FROM #mike_temp b where a.state = b.state FOR XML PATH('')),1, 2, '') AS CSVColumn
from #mike_temp a
答案 2 :(得分:1)
在SQL Server 2017中添加了STRING_AGG功能
SELECT t.name as TableName
,STRING_AGG(c.name, ';') AS FieldList
FROM sys.tables t
JOIN sys.columns c
ON t.object_id = c.object_id
GROUP BY t.name;
答案 3 :(得分:0)
AFAIK,你需要自己做。
您可以构建一个用户定义的函数,该函数使用游标循环其中状态为CA的Employee记录并返回其名称的串联。
答案 4 :(得分:0)
SELECT Field1, Substring(Field2, 2, LEN(Field2)) AS Field2 FROM
(
SELECT
[InnerData].Field1,
(SELECT ',' + Field2 FROM @Fields WHERE Field1=[InnerData].Field1 FOR XML PATH('')) AS Field2
FROM
(
SELECT DISTINCT Field1 FROM @Fields
) AS [InnerData]
) AS OuterData
我从此链接
获得此查询答案 5 :(得分:-3)
试试这个
select
wm_concat(name)
from
employee
where
state='CA'
group by
state