我的程序如下所示
我写了以下示例程序。我不认为这是正确的方法。有没有更好的方法?在这个prg中,我不确定何时调用interupt方法。
public class MethodTimeout implements Runnable{
/**
* @param args
*/
public Thread t1 = null;
public int threadnum = 0;
public static void main(String[] args) {
for (int i=0; i<3; i++){
MethodTimeout mt =new MethodTimeout();
Thread t = new Thread(mt,"thread "+(i+1));
mt.t1 = t;
mt.threadnum = (i+1);
t.start();
}
System.out.println("stmt after execution");
}
public Object testTimeout(){
long startTime = System.currentTimeMillis();
try {
System.out.println("in side method start "+t1.getName()+" start time"+startTime);
Thread.sleep(5000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
long endtime = System.currentTimeMillis();
System.out.println("in side method end "+t1.getName()+" total time"+(endtime-startTime) );
return null;
}
@Override
public void run() {
Thread timeout = new Thread (){
public void run() {
testTimeout();
};
};
timeout.start();
try {
Thread.sleep(2000);
timeout.interrupt();
Thread.sleep(2000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println(t1.getName() + " is ending");
}
}
答案 0 :(得分:1)
听起来你应该实现Callable。 这只是一个例子
import java.util.concurrent.Callable;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.TimeoutException;
public class Test {
public static void main(String[] args) throws Exception {
ExecutorService service = Executors.newFixedThreadPool(2);
Future<String> futureResult = service.submit(new MyCall());
try{
String result = futureResult.get(20, TimeUnit.MILLISECONDS);
} catch(TimeoutException timeout){
System.out.println("Timeout");
service.shutdownNow();
}
}
static class MyCall implements Callable<String> {
@Override
public String call() throws Exception {
try{
//Simulate some corba work
Thread.sleep(1000);
}catch(InterruptedException e){
Thread.currentThread().interrupt();
System.out.println("Shutting down the task!");
}
return "The result";
}
}
}
答案 1 :(得分:0)
您还可以对@ Eugene的答案进行一次小的更改,而不是在shutdownNow()
上调用ExecutorService
,而只需在cancel(true)
上调用futureResult
{1}}超时了。以下是代码段:
public class Test {
public static void main(String[] args) throws Exception {
ExecutorService service = Executors.newFixedThreadPool(2);
Future<String> futureResult = service.submit(new MyCall());
try{
String result = futureResult.get(20, TimeUnit.MILLISECONDS);
} catch(TimeoutException timeout){
System.out.println("Timeout");
} finally {
futureResult.cancel(true);
}
}
这只是为了确保只取消超时线程。由于shutdownNow()
除了试图停止当前正在执行的任务外,还会阻止等待任务的启动。