我有2个表预订和消息,现在我想在收件箱中一次显示预订请求和消息。
$this->paginate = array(
'conditions' => $conditions,'limit' =>10,
'order'=>array('Booking.created'=>'DESC'));
$bookings = $this->paginate('Booking');
$this->paginate = array(
'conditions' => $conditions,'limit' =>10,
'order'=>array('MessageDetail.created'=>'DESC'));
$messages = $this->paginate('MessageDetail');
我合并了两个表数据(array_merge($ bookings,$ messages);) 现在我想按日期排序(或任何条件)
Array
(
[0] => Array
(
[Booking] => Array
(
[id] => 4
[host_id] => 21
[place_id] => 10
[room_id] => 13
[user_id] => 12
[message_detail_id] => 16
[created] => 2013-04-23 14:44:03
[accept_date] =>
[cancel_date] =>
)
)
[1] => Array
(
[Booking] => Array
(
[id] => 3
[host_id] => 21
[place_id] => 10
[room_id] => 13
[user_id] => 12
[message_detail_id] => 13
[created] => 2013-04-15 14:10:59
[accept_date] => 2013-04-15 14:40:47
[cancel_date] =>
)
)
[2] => Array
(
[MessageDetail] => Array
(
[id] => 17
[message_id] => 2
[user_id] => 12
[sender_id] => 21
[unread] => 0
[created] => 2013-04-24 12:11:47
)
)
[3] => Array
(
[MessageDetail] => Array
(
[id] => 15
[message_id] => 2
[user_id] => 12
[sender_id] => 21
[booking_id] => 3
[unread] => 0
[created] => 2013-04-15 15:01:12
)
)
)
提前致谢。
答案 0 :(得分:0)
选项#1: 创建名为" BookingAndMessage"的第三个模型。您可以使用Model的afterSave方法(在Booking和Message上)在新模型中创建重复记录。然后,您可以按正确的排序顺序查询BookingAndMessage。
选项#2 :要解决问题,您需要使用PHP的usort函数(此处也解释为PHP Sort a multidimensional array by element containing date)。
<?php
$BookingsAndMessages = array_merge($bookings, $messages);
function date_compare($a, $b)
{
$modelKeyA = array_key_exists('Booking',$a) ? 'Booking' : 'MessageDetail';
$modelKeyB = array_key_exists('Booking',$b) ? 'Booking' : 'MessageDetail';
$t1 = strtotime($a[$modelKeyA]['created']);
$t2 = strtotime($b[$modelKeyB]['created']);
return $t1 - $t2;
}
usort($BookingsAndMessages, 'date_compare');
// Would sort the merged records by `created` date
?>
选项2的缺点是,您必须为每个字段(以及排序方向)创建规则。