Question

我需要对包含时间NSArray的{{1}}进行排序，例如，

NSString

我需要的是按照时间的升序对数组进行排序有没有办法做这样的事情？

Answer 1

NSMutableArray *times = [[NSMutableArray alloc]initWithObjects:@"09:00 AM",@"07:30 AM",@"06:45 PM",@"05:00 PM",@"12:45 AM",@"12:45 PM",@"01:00 AM",@"01:15 PM", nil];

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"hh:mm a"];

NSArray *sortedTimes = [times sortedArrayUsingComparator:^NSComparisonResult(NSString *obj1, NSString *obj2)
{
    NSDate *date1 = [dateFormatter dateFromString:obj1];
    NSDate *date2 = [dateFormatter dateFromString:obj2];
    return [date1 compare:date2];
}];

优化版：

NSMutableArray *times = [[NSMutableArray alloc]initWithObjects:@"09:00 AM",@"07:30 AM",@"06:45 PM",@"05:00 PM",@"12:45 AM",@"12:45 PM",@"01:00 AM",@"01:15 PM", nil];

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"hh:mm a"];

NSMutableArray *dates = [NSMutableArray arrayWithCapacity:times.count];
for (NSString *timeString in times)
{
    NSDate *date = [dateFormatter dateFromString:timeString];
    [dates addObject:date];
}

[dates sortUsingSelector:@selector(compare:)];

NSMutableArray *sortedTimes = [NSMutableArray arrayWithCapacity:dates.count];
for (NSDate *date in dates)
{
    NSString *timeString = [dateFormatter stringFromDate:date];
    [sortedTimes addObject:timeString];
}

Answer 2

您可以尝试以下代码：

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
    [formatter setDateFormat:@"hh:mm a"];
    [times sortUsingComparator:^NSComparisonResult(NSString* obj1, NSString *obj2) {
        NSDate *firstDate = [formatter dateFromString:obj1];
        NSDate *secondDate = [formatter dateFromString:obj2];
        return [firstDate compare:secondDate];
    }];

Answer 3

因为这些是字符串，所以它将被视为

01：15,12：25,05：00 ....

他们不是NSDate。

所以你需要做的是从这些字符串中创建一个具有NSDate的并行数组，对数组进行排序，然后提取这些值。

实施时，我通过新手方式解决了它

NSMutableArray *times = [[NSMutableArray alloc]initWithObjects:@"09:00 AM",@"07:30 AM",@"06:45 PM",@"05:00 PM",@"12:45 AM",@"12:45 PM",@"01:00 AM",@"01:15 PM", nil];

NSMutableArray *dates=[NSMutableArray new];

NSDateFormatter *dateFormatter=[NSDateFormatter new];
[dateFormatter setDateFormat:@"hh:mm a"];

for (NSString *stringDate in times) {
        NSDate *date=[dateFormatter dateFromString:stringDate];
        [dates addObject:date];
}

NSSortDescriptor *descriptor = [[NSSortDescriptor alloc] initWithKey:@"self" ascending:YES];
NSArray *descriptors = [NSArray arrayWithObject: descriptor];
NSArray *reverseOrder = [dates sortedArrayUsingDescriptors:descriptors];

[times removeAllObjects];
for (NSDate *date in reverseOrder) {
        NSString *string=[dateFormatter stringFromDate:date];
        [times addObject:string];
}

NSLog(@"%@",times);

Answer 4

对于NSDate比较，请使用：

+ (BOOL)isDate:(NSDate *)date1 smallerThanAnotherDate:(NSDate *)date2
{
    NSDate* enddate = date1;
    NSDate* currentdate = date2;
    NSTimeInterval distanceBetweenDates = [enddate timeIntervalSinceDate:currentdate];
    double secondsInMinute = 60;
    NSInteger secondsBetweenDates = distanceBetweenDates / secondsInMinute;

    if (secondsBetweenDates == 0)
        return YES;
    else if (secondsBetweenDates < 0)
        return YES;
    else
        return NO;
}

所以，如果你不想将你的小时数转换为NSDate，那么单独这样做对我有用

NSArray *sortedTimes =  [times sortedArrayUsingSelector:@selector(localizedStandardCompare:)];

iOS排序时间NSString的NSArray

4 个答案: