我一直致力于阅读文本文件并将文本组织成每个项目的块。我需要帮助找出在程序使用过程中可以保存和调用数据的方法。我试图将输出作为数据网格视图。我不知道如何处理这个问题。我想我可以为每个新块创建一个数据表,但我不知道该怎么做。
到目前为止我的代码:
public void findBlocks()
{
String fileName = "Drops.de";
StreamReader streamReader = new StreamReader(fileName);
String npcName;
string npcID;
string itemID;
string itemAmount;
string itemRarity;
string itemName;
while(!streamReader.EndOfStream){
string line = streamReader.ReadLine();
//start of block
if(line.StartsWith("[")){
npcName = line.TrimStart('[');
npcName = npcName.TrimEnd(']');
while(!line.StartsWith("[/")){
line = streamReader.ReadLine();
String[] s = line.Split(' ');
npcID = (s[0]);
itemName = (s[1]);
itemID = (s[2]);
itemAmount = (s[3]);
itemRarity = (s[4]);
DataTable dt = new DataTable();
DataGridViewRow dgv = new DataGridViewRow();
DataGridViewRow row = (DataGridViewRow)dataGridView1.Rows[0].Clone();
row.Cells[0].Value = itemName;
row.Cells[1].Value = itemID;
row.Cells[2].Value = itemAmount;
row.Cells[3].Value = itemRarity;
dataGridView1.Rows.Add(row);
dataGridView1.Refresh();
line = streamReader.ReadLine();
//MessageBox.Show(npcName);
}
}
}
}
private void button2_Click(object sender, EventArgs e)
{
search();
}
public void loadItemList(string file)
{
String fileName = file;
StreamReader streamReader = new StreamReader(fileName);
while (!streamReader.EndOfStream)
{
string currentLine = streamReader.ReadLine();
string s;
String id;
String itemName = "";
if (currentLine.Contains("item"))
{
s = currentLine.TrimStart('i', 't', 'e', 'm', ' ', '=', ' ');
id = s.Split('.')[0];
itemName = id.Split('\t')[1];
id = id.Split('\t')[0];
listBox1.Items.Add(itemName + " " + id);
}
else
{
streamReader.ReadLine();
}
}
streamReader.Close();
}
这是我尝试排序的文本文件的示例:
[item1]
2550 coins 995 200000 7
2550 coins 995 200000 7
2550 coins 995 200000 7
2550 coins 995 200000 7
2550 coins 995 200000 7
[/item1]
[item2]
2550 coins 995 200000 7
2550 coins 995 200000 7
2550 coins 995 200000 7
2550 coins 995 200000 7
2550 coins 995 200000 7
[/item2]
[item3]
2550 coins 995 200000 7
2550 coins 995 200000 7
2550 coins 995 200000 7
2550 coins 995 200000 7
2550 coins 995 200000 7
[/item3]
等。
非常感谢任何和所有帮助:)
答案 0 :(得分:1)
可以找到示例帖子here,下面列出了关键步骤:
示例代码可能是:
[Serializable]
class SomeProperty
{
public int Count1 {get;set;} //2550
public int Count2 {get;set;} //995
public int Count3 {get;set;} //200000
public int Count4 {get;set;} //7
}
List<SomeProperty> objects=new List<SomeProperty>();
objects.Add(...)
//Saving
XmlSerializer x = new XmlSerializer(objects.GetType());
using (FileStream stream = System.IO.File.Create(FilePath))
{
XmlWriter writer = XmlWriter.Create(stream);
x.Serialize(writer, objects);
}
//Reading
XmlSerializer x = new XmlSerializer(typeof(List<SomeProperty>));
using (FileStream fs = new FileStream(FilePath, FileMode.Open))
{
XmlReader reader = new XmlTextReader(fs);
var objects= (List<SomeProperty>)x.Deserialize(reader);
}