如何使用可选的上传文件提交表单数据。我的意思是，我可以将表单数据与上传的文件一起提交吗？但我想让上传文件可选。这是我的代码：
<?php
define ("MAX_SIZE","5000");
$errors=0;
if(($_SERVER["REQUEST_METHOD"] == "POST") && isset($_FILES["file"]["size"]) && ($_FILES["file"]["size"] > 0))
{
$image =$_FILES["file"]["name"];
$uploadedfile = $_FILES['file']['tmp_name'];
if ($image)
{
$filename = stripslashes($_FILES['file']['name']);
$extension = getExtension($filename);
$extension = strtolower($extension);
if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))
{
$change='<div class="msgdiv">Unknown Image extension </div> ';
$errors=1;
}
else
{
$size=filesize($_FILES['file']['tmp_name']);
if ($size > MAX_SIZE*1024)
{
$change='<div class="msgdiv">You have exceeded the size limit!</div> ';
$errors=1;
}
if($extension=="jpg" || $extension=="jpeg" )
{
$uploadedfile = $_FILES['file']['tmp_name'];
$src = imagecreatefromjpeg($uploadedfile);
}
else if($extension=="png")
{
$uploadedfile = $_FILES['file']['tmp_name'];
$src = imagecreatefrompng($uploadedfile);
}
else
{
$src = imagecreatefromgif($uploadedfile);
}
echo $scr;
list($width,$height)=getimagesize($uploadedfile);
$newwidth=500;
$newheight=($height/$width)*$newwidth;
$tmp=imagecreatetruecolor($newwidth,$newheight);
$newwidth1=300;
$newheight1=($height/$width)*$newwidth1;
$tmp1=imagecreatetruecolor($newwidth1,$newheight1);
imagealphablending($tmp1, false);
imagesavealpha($tmp1, true);
imagecopyresampled($tmp,$src,0,0,0,0,$newwidth,$newheight,$width,$height);
imagecopyresampled($tmp1,$src,0,0,0,0,$newwidth1,$newheight1,$width,$height);
$image_name=time().'_'.$_FILES['file']['name'];
$filename = "images/". $image_name;
$filename1 = "images/small_". $image_name;
$uid=$_SESSION['uid'];
imagejpeg($tmp,$filename,100);
imagejpeg($tmp1,$filename1,100);
imagedestroy($src);
imagedestroy($tmp);
imagedestroy($tmp1);
}}
}
if(isset($_POST['Submit']) && !$errors )
{
$category_group= $_POST['category_group'];
$title=$_POST['title'];
$details=$_POST['details'];
$ad_keywords=$_POST['ad_keywords'];
$category_state=$_POST['category_state'];
$category_city=$_POST['category_city'];
$address=$_POST['address'];
$telephone=$_POST['telephone'];
$email=$_POST['email'];
$website=$_POST['website_link'];
$price=$_POST['price'];
$filename= ($_FILES["file"]["size"] > 0) ? $filename : '';
$filename1= ($_FILES["file"]["size"] > 0) ? $filename1 : '';
$url=time().'-'. createUrl($title);
if(!$category_group || !category_city || !$title || !$details || !$category_state ){
echo "enter state and city name";
}else{
try{
$sth = $dbh->prepare("
INSERT INTO
advertisement(user_id,ad_image_big,ad_image_small,ad_cat_group,ad_title,ad_details,ad_state,ad_city,ad_address,ad_telephone,ad_email,ad_website,ad_price,ad_slug,ad_keywords)
VALUES(:field1,:field2,:field3,:field4,:field5,:field6,:field7,:field8,:field9,:field10,:field11,:field12,:field13,:field14,:field15)
");
$sth->execute(array(':field1' => $uid, ':field2' => $filename, ':field3' => $filename1, ':field4' => $category_group, ':field5' => $title, ':field6' => $details, ':field7' => $category_state,':field8'=> $category_city, ':field9' => $address, ':field10' => $telephone,':field11'=> $email,':field12'=> $website, ':field13' => $price, ':field14' => $url , ':field15'=> $ad_keywords));
}catch (PDOException $ex){
echo "An Error occured while inserting data to database";
some_logging_function($ex->getMessage());
}
header('location:success.php');
}
}
?>
每当我尝试提交没有上传文件的表单时，我都会收到此错误：
“将数据插入数据库时出错”
位于catch部分。如果我上传文件，我会收到一条成功的消息而没有任何错误。请帮帮我。
答案 0 :(得分：1)
这是我不久前制作的代码......有同样的问题：）
表单本身：
<form action="index.php" method="post" enctype='multipart/form-data'>
<input class="header_input" type="text" name="header" />
<br/><span class="input_headers"><p>Content</p></span>
<textarea class="textarea_input" rows="10" cols="30" name="content">
</textarea><br />
Select File: <input type='file' name='filename' size='10' /><br />
<input type="submit" class="submit" />
</form>
虽然它没有检查，但有些内容被输入“标题”和“内容”部分，所以试着解决这个问题：
if (isset($_POST['header']) && isset($_POST['content'])) {
$header = mysql_real_escape_string(htmlentities($_POST['header']));
$content = mysql_real_escape_string(nl2br(htmlentities($_POST['content'])));
$sql = mysqli_query($con,"INSERT INTO posts (Header, Content) VALUES
('{$header}','{$content}')");
}
这会上传图片，如果有的话：
if (isset($_FILES['filename']['name'])) {
$name = htmlentities($_FILES['filename']['name']);
$allowedExts = array("gif", "jpeg", "jpg", "png");
$extension = end(explode(".", $_FILES['filename']['name']));
if ((($_FILES['filename']['type'] == "image/gif")
|| ($_FILES['filename']['type'] == "image/jpeg")
|| ($_FILES['filename']['type'] == "image/jpg")
|| ($_FILES['filename']['type'] == "image/pjpeg")
|| ($_FILES['filename']['type'] == "image/x-png")
|| ($_FILES['filename']['type'] == "image/png"))
&& ($_FILES['filename']['type'] < 20000)
&& in_array($extension, $allowedExts)) {
$result = mysqli_query($con,"SELECT * FROM posts WHERE PID=(SELECT max(PID) FROM posts)");
$row = mysqli_fetch_array($result);
$id = $row['PID'];
$new_name = $id . "_" . "000" . ".jpg";
if (file_exists("images/" . $new_name)) {
$new_name_ex = $id . "_" . "001" . ".jpg";
move_uploaded_file($_FILES['filename']['tmp_name'],"images/" . $new_name_ex);
$sql = mysqli_query($con,"UPDATE posts SET Images='{$new_name_ex}' WHERE PID='{$id}'");
} else {
move_uploaded_file($_FILES['filename']['tmp_name'],"images/" . $new_name);
$sql = mysqli_query($con,"UPDATE posts SET Images='{$new_name}' WHERE PID='{$id}'");
}
}
}
希望有所帮助:)我是PHP新手，所以也许有办法让所有这些代码更简单，我希望它能回答你的问题
答案 1 :(得分：1)
从PHP文档（http://php.net/manual/en/features.file-upload.post-method.php），示例＃3上传文件数组可以完成您遍历每个文件所需的内容（如果您有一个文件数组），那么 if语句检查文件是否存在。下面的代码来自PHP文档：
foreach ($_FILES["pictures"]["error"] as $key => $error) {
if ($error == UPLOAD_ERR_OK) {
$tmp_name = $_FILES["pictures"]["tmp_name"][$key];
$name = $_FILES["pictures"]["name"][$key];
move_uploaded_file($tmp_name, "data/$name");
}
}
如果没有文件，代码只会跳过上传并继续下一步。